Answer:HERE IS YOUR ANSWER
THE POINTS ARE
IF WE PUT THE OBJECT BETWEEN THE FOCUS
AND THE POLE
THEN THE IMAGE FORMED WILL be MAGNIFIED
If that’s not what you are looking for, try this one:
For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.
Given here the "size of the image" is twice to that of the object.
Hence, it is consider that the magnification is +2.
So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."
Explanation:
I do weight lifting so you need feet flat on floor but out back straight and also a spotter
All of that fluff at the beginning is interesting, but completely irrelevant
to the question. The question is just asking for the mass of an object
that weighs 3.6N on Earth.
Weight = (mass) x (acceleration of gravity)
3.6N = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s : Mass = 3.6N / 9.8 m/s² = <em>0.367 kilogram</em> (rounded)
The increase in speed leads to an increase in the amount of air resistance. Eventually, the force of air resistance becomes large enough to balances the force of gravity. At this instant in time, the net force is 0 Newton; the object will stop accelerating. The object is said to have reached a terminal velocity.
