Respuesta: verifique amablemente la explicación
Explicación:
Dado lo siguiente:
Longitud (L) del cable = 120 m
Diámetro (d) = 2,2 mm (2,2 / 1000) = 2,2 * 10 ^ -3 m
Fuerza (F) = 380 N
Esfuerzo longitudinal = Fuerza / Área
Área = πd² / 4 = (π * (2.2 * 10 ^ -3) ^ 2) / 4
Área = (3.142 * 4.84 * 10 ^ -6)
Área = 0.00000380132 m²
Estrés = Fuerza / Área
Estrés = 380 / 0.00000380132
Esfuerzo longitudinal = 99952128.12 = 9.9952128 * 10^7 Nm^-2
Deformación longitudinal: extensión / longitud
Extensión = 0.10 m
Longitud = 120 m
Deformación longitudinal = 0,1 m / 120 m
Deformación longitudinal = 0.0008333 = 8.33 × 10 ^ -4
Answer:
4.0 m/s
Explanation:
The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.
Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

where here we have
d = 3.0 m is the horizontal distance covered
vx is the horizontal velocity
t = 1.3 s is the duration of the fall
Solving for vx,

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

where
h = 4.0 m is the initial height
vy is the initial vertical velocity
We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

So now we can find the magnitude of the initial velocity:

Answer:
Electric force, 
Explanation:
It is given that,
Charge on an electron is 
Electric field, 
We need to find the magnitude of the electric force on this electron due to this field. The electric force is given by :

So, the electric force is
.
Answer:
a= 23.65 ft/s²
Explanation:
given
r= 14.34m
ω=3.65rad/s
Ф=Ф₀ + ωt
t = Ф - Ф₀/ω
= (98-0)×
/3.65
98°= 1.71042 rad
1.7104/3.65
t= 0.47 s
r₁(not given)
assuming r₁ =20 in
r₁ = r₀ + ut(uniform motion)
u = r₁ - r₀/t
r₀ = 14.34 in= 1.195 ft
r₁ = 20 in = 1.67 ft
= (1.667 - 1.195)/0.47
0.472/0.47
u= 1.00ft/s
acceleration at collar p
a=rω²
= 1.67 × 3.65²
a = 22.25ft/s²
acceleration of collar p related to the rod = 0
coriolis acceleration = 2ωu
= 2× 3.65×1 = 7.3 ft/s²
acceleration of collar p
= 22.5j + 0 + 7.3i
√(22.5² + 7.3²)
the magnitude of the acceleration of the collar P just as it reaches B in ft/s²
a= 23.65 ft/s²
Answer:
v = 2591.83 m/s
Explanation:
Given that,
The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

So, the speed of the electron is 2591.83 m/s.