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3 years ago

The chemical equation for the decomposition of potassium chlorate into potassium chloride and oxygen gas is

Physics

1 answer:

brilliants [131]3 years ago

5 0

Answer:

Option C. 2, 2, 3

Explanation:

__KClO₃ —> __ KCl + __O₂

The above equation can be balance as illustrated below:

KClO₃ —> KCl + O₂

There are 2 atoms of O on the right side and 3 atoms on the left side. It can be balance by writing 2 before KClO₃ and 3 before O₂ as shown below:

2KClO₃ —> KCl + 3O₂

There are 2 atoms of K on the left side and 1 atom on the right side. It can be balance by writing 2 before KCl as shown below:

2KClO₃ —> 2KCl + 3O₂

Thus, the equation is balanced. The coefficients are: 2, 2, 3

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yaroslaw [1]

Answer: Electromagnetic radiation

Explanation:

Electromagnetic radiation is a combination of oscillating electric and magnetic fields, which propagate through space carrying energy from one place to another.

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3 years ago

Which of the following is an inclined plane wrapped around a rod?

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4 years ago

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During a shock which lasts 10ms (0.01s), the voltage difference between the electrodes (so the drop in potential across all thre

natta225 [31]

Answer:

20000 W

Explanation:

Power: This can be defined as the rate at which energy is dissipated or used. The S.I unit of power is Watt(W).

The expression of power is given as,

P = E/t.............................. Equation 1

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3 years ago

Robin fired a bullet of mass 100 gm from a gun of mass 5 kg. The bullet leaves the gun with a speed of 400 m/s. After penetratin

Marina CMI [18]

(a) the recoil or backward velocity of the gun is 8 m/s.

(b) the bullet cannot completely penetrate the plank.

The given parameters include;

mass of the bullet, m₁ = 100 g = 0.1 kg

mass of the gun, m₂ = 5 kg

initial velocity of the bullet, u₁ = 400 m/s

thickness of the plank, x = 10 cm

To calculate the following:

(a) the backward velocity of the gun

let the backward velocity of the gun = u₂

Apply the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = 0

m₂u₂ = -m₁u₁

$u_2 = -\frac{m_1u_1}{m_2} \\\\u_2 = - \frac{0.1 \times 400}{5} \\\\u_2 = -8 \ m/s$

Thus, the recoil or backward velocity of the gun is 8 m/s.

(b) Can the bullet penetrate the plank of the wood completely ?

the bullet traveled 4 cm and lost ¹/₃ of u₁

the remaining distance to completely penetrate the plank = 6 cm

the final velocity of the bullet at 4 cm, v = 400 - ¹/₃ x 400 m/s = 266.67 m/s

the acceleration of the bullet is calculated as;

v² = u₁² + 2as

2as = v² - u²

$a = \frac{v^2 -u_1^2}{2s} \\\\a = \frac{(266.67)^2 -(400)^2}{2\times 0.04} = -1.111 \times 10^6 \ m/s^2$

Finally, determine the distance traveled by the bullet when it comes to a complete stop, that is the final velocity = 0

$v_f^2 = v^2 + 2ad\\\\2ad = v_f^2 - v^2\\\\d = \frac{v_f^2 - v^2}{2a} \\\\d = \frac{(0) - (266.67)^2}{2(-1.111\times 10^6)} \\\\d = 0.032 \ m$

d = 3.2 cm

The total distance traveled by the bullet inside the plank = 4 cm + 3.2 cm = 7.2 cm

Therefore, the bullet cannot completely penetrate the plank.

To learn more about linear momentum visit: brainly.com/question/15869303

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3 years ago