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3 years ago

How do leptons differ from hadrons?

1 answer:

4 0

I'll just give you the link for it but count it as my answer. http://www.differencebetween.com/difference-between-leptons-and-vs-hadrons/

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PLSS HELP AND I WILL GIVE BRAINLY TO THE ONE WHO ANSWERS CORRECTLY

Ierofanga [76]

The potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The energy in terms of the charge and potential difference is;

E= qV

60=5 C × V

V= 12 V

The electric current is found as;

$\rm I= \frac{q}{t} \\\\ I= \frac{5}{1.25}\\\\ I=4 \ A$

From the ohm's law;

V=IR

12=4 ×R

R=3Ω

If the voltage is constant and the resistance is doubled, then the new electric current is half of the previous condition;

$\rm I'=\frac{I}{2} \\\\ I'=\frac{4}{2} \\\\\ I'=2 \ A$

Hence, the potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

To learn more about the resistance, refer to the link;

brainly.com/question/20708652

#SPJ1

7 0

1 year ago

A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.

wlad13 [49]

9.81m/s^2 x .27 = 2.6487m/s

8 0

2 years ago

Boxes are transported from one location to another in a warehouse by means of a conveyor belt that moves with a constant speed o

krek1111 [17]

Answer:

P = 15.90 W

Explanation:

given,

speed of conveyor belt = 0.56 m/s

conveyor belt move up to = 2 m

angle made with the horizontal = 15°

mass of the box = 2.1 kg

rate is the force of the conveyor belt doing work on the box as the box moves up

P = F v cos ∅

P = 3 × 9.8 × 0.56 × cos 15°

P = 15.90 W

6 0

2 years ago

If the area is 2 square meters (2 m²), what's the force of gravity acting on the column of water?

-Dominant- [34]

What area ?

What column of water ?

6 0

2 years ago

When power and current are known use R = P/I^2 to calculate the resistance.

inna [77]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf• \: Power \:( P) = 300 \: watts$

$\sf• \: Current \: (I) = 30 \: amps$

$\\$

<h2> $\bf{ \underline{To \: Find:- }}$ </h2>

$\sf• \: The \: Resistance$

$\\$

$\huge\bf{ \underline{Solution :-:- }}$

$\bf \red {\bigstar{ Formula \: of \: Power \: (P) = \frac{ {I}^{2} }{R}}}$

$\sf \rightarrow 300= \frac{ {30}^{2} }{ R}$

$\sf \rightarrow 300 = \frac{900}{ R}$

$\rightarrow \sf R = \frac{300}{900}$

$\rightarrow \sf R = \frac{1}{3}$

$\rightarrow \sf R = 0.33$

$\bf \purple{Hence, \: the \: resistance \: is \: 0.33 \: Ω \: . }$

7 0

2 years ago