Explanation:
In the picture, I hope that it's a clear solution.
Answer:
s=1/2at²+v(initial)t
s=1/2(3)(30)²+(0)(30)
s=1/2(3)(30)²+0
s=900(1/2)(3)
s=450(3)
s=1350m
Explanation: -is this what your looking for?
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Answer:
The magnitude of force on P is 2.75 N
The magnitude of force on Q is 7.15 N
Solution:
As per the question:
Mass of the object, M = 11.0 kg
Acceleration of the object when the forces are directed leftwards, a =
Acceleration when the forces are in opposite direction, a' =
Now,
The net force on the object in first case is given by:
(1)
The net force on the object in second case is given by:
(2)
Adding both eqn (1) and (2):
Putting the above value in eqn (1):
First let us calculate for the angle of inclination using
the sin function,
sin θ = 1 m / 4 m
θ = 14.48°
Then we calculate the work done by the movers using the
formula:
W = Fnet * d
So we must calculate for the value of Fnet first. Fnet is
force due to weight minus the frictional force.
Fnet = m g sinθ – μ m g cosθ
Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48
Fnet = 84.526 N
So the work exerted is equal to:
W = 84.526 N * 4 m
<span>W = 338.10 J</span>