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Gre4nikov [31]
4 years ago
9

How do leptons differ from hadrons?

Physics
1 answer:
Savatey [412]4 years ago
4 0
I'll just give you the link for it but count it as my answer. http://www.differencebetween.com/difference-between-leptons-and-vs-hadrons/
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A dart is thrown horizontally at a target's center that is 5.00 m, away. The dart hits the target 0.150 m below the targets cent
boyakko [2]

Answer:

  v₀ₓ = 28.6 m / s

Explanation:

This is a missile throwing exercise

          y = v_{oy} t - ½ g t²

as the dart is thrown horizontally the vertical velocity is zero (I go = 0)

          y = - ½ g t²

          t = \sqrt{- \frac{2y}{g}  }

let's calculate

         t = \sqrt{- \frac{2 \  (-0.150)}{9.8} }

         t = 0.175 s

the expression for horizontal displacement is

         x = v₀ₓ t

         v₀ₓ = x / t

         v₀ₓ = 5.00 / 0.175

         v₀ₓ = 28.6 m / s

7 0
3 years ago
Is anyone online??just asking ​
lianna [129]

Answer:

me...:(

Explanation:

3 0
3 years ago
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A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra
sergey [27]

Answer:

\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

      The  radius is  r =  1.17 \ cm =  0.0117 \ m

       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

       The  induced emf is  e  =  8.20 *10^{-6} \  V/m

Generally according to Gauss law

        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

=>    e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  A

Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

=>       \frac{di}{dt}  =  \frac{2e * x  }{\mu_o * N  * r^2}ggl;

Here  \mu_o is the permeability of free space with value

          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

6 0
4 years ago
ASAP HELP!!
rodikova [14]
The force of gravity between two objects is increased when the mass of objects is increased.
3 0
4 years ago
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Every object that has mass attracts every other object with a gravitational force: It has been proven that the size of the
denpristay [2]

Answer:

this is a law because it is a constant fact of nature

Explanation:

7 0
3 years ago
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