How much heat is released to freeze 47.30 grams of copper at its freezing point of 1,085°C? The latent heat of fusion of copper
2 answers:
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Answer:
E = 31.329 N/C.
Explanation:
The differential electric field at the center of curvature of the arc is
<em>(we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )</em>
where is the radius of curvature.
Now
,
where is the charge per unit length, and it has the value
Thus, the electric field at the center of the curvature of the arc is:
Now, we find and
. To do this we ask ourselves what fraction is the arc length 3.0 of the circumference of the circle:
and this is
radians.
Therefore,
evaluating the integral, and putting in the numerical values we get:
Answer:
The inductor contains loops
Explanation:
From the question we are told that
The capacitance of the capacitor is
The resonance frequency is
The diameter is
The of the air-core inductor is
The permeability of free space is
Generally the inductance of this air-core inductor is mathematically represented as
This inductance can also be mathematically represented as
Where is the angular speed mathematically given as
So
Now equating the both formulas for inductance
making N the subject of the formula
Substituting value
loops