How much heat is released to freeze 47.30 grams of copper at its freezing point of 1,085°C? The latent heat of fusion of copper
2 answers:
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A) See ray diagram in attachment (-6.0 cm)
By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:
where
q is the distance of the image from the lens
f = -10 cm is the focal length (negative for a diverging lens)
p = 15 cm is the distance of the object from the lens
Solving for q,
B) The image is upright
As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:
where are the size of the image and of the object, respectively.
Since q < 0 and p > o, we have that , which means that the image is upright.
C) The image is virtual
As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.
This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual
Answer:
6.7 m/s^2
Explanation:
The formula of acceleration is:
where is acceleration,
is velocity and
is time.
means final velocity.
means initial velocity,
means final time and
means initial time.
We are given that the Firebird travels at velocity of 0 to 60 mph in four seconds. Therefore:
- Our initial velocity starts at 0 mph.
- Our final velocity is at 60 mph.
- Our initial time is 0 second.
- Our final time is 4 seconds.
Since it travels to the east then our vector will be positive. However, acceleration has to be in m/s^2 unit (Sl unit) so we'll have to convert from mph (miles per hours) to m/s (meters per second) first.
We know that:
- A mile equals to 1609.344 meters.
- An hour equals to 60 minutes which a minute equals to 60 seconds. So 60 minutes will equal to 3600 seconds.
Now we divide 1609.344 by 3600 to find a unit rate of m/s:
Now multiply 0.44704 m/s by 0 and 60 to get velocity in m/s unit:
- Initial velocity = 0 m/s
- Final velocity = 60 * 0.44704 = 26.82 m/s
Time is already in second so no need for conversion. Substitute known information in the formula:
Therefore, the Firebird will accelerate at the rate of 6.7 m/s^2.