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Nesterboy [21]
4 years ago
8

2) The horizontal and vertical components of the initial velocity of a football are 16 m/s and 20 m/s respectively. How long doe

s it take for the football to rise to the highest point of its trajectory?
Physics
1 answer:
ValentinkaMS [17]4 years ago
5 0

Answer: 2.04 s

Explanation:

Let the initial velocity be v, Angle of projectile be

Then the horizontal component = v cos θ = 16 m/s

Vertical component of velocity = v sin θ = 20 m/s

Time taken to reach the highest point is half the time taken for total flight.

Time for total flight,

t = \frac{2vsin \theta}{g}

t'=\frac{vsin \theta}{g} = \frac {20 m/s}{9.8 m/s^2} = 2.04 s

Thus, the football takes 2.04 s to rise to the highest point of its trajectory.

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You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.
babymother [125]

Answer:

Mass of the planet = 1.48 × 10²⁵ Kg

Mass of the star = 5.09 × 10³⁰ kg

Explanation:

Given;

Diameter = 1.8 × 10⁷ m

Therefore,

Radius = \frac{\textup{Diameter}}{\textup{2}}  = \frac{\textup{1.8}\times10^7}{\textup{2}}

or

Radius of the planet = 0.9 × 10⁷ m

Rotation period = 22.3 hours

Radius of star = 2.2 × 10¹¹ m

Orbit period = 407 earth days = 407 × 24 × 60 × 60 seconds = 35164800 s

free-fall acceleration = 12.2 m/s²

Now,

we have the relation

g = \frac{\textup{GM}}{\textup{R}^2}

g is the free fall acceleration

G is the gravitational force constant

M is the mass of the planet

on substituting the respective values, we get

12.2 = \frac{6.67\times10^{-11}\times M}{(0.9\times10^7)^2}

or

M = 1.48 × 10²⁵ Kg

From the Kepler's law we have

T² = \frac{\textup{4}\pi^2}{\textup{G}M_{star}}(R_{star})^3

on substituting the respective values, we get

35164800² = \frac{\textup{4}\pi^2}{6.67\times10^{-11}\timesM_{star}}(2.2\times10^{11})^3

or

M_{star} = 5.09 × 10³⁰ kg

6 0
3 years ago
What is the tendency of a material to oppose the flow of charge?
elena55 [62]

I think the answer is Resistance.  If the link i posted int he comment is right.

8 0
4 years ago
Why do animals use echolocation? Check all that apply.
jenyasd209 [6]
To find food to find each other and to find their way
7 0
4 years ago
Read 2 more answers
Consider the reaction X mc022-1.jpg Y + 2Z . If the molar solubility of X is multiplied by 2, the value of Ksp will be multiplie
Alex777 [14]
X -> Y + 2Z

So there are 2 different particles. 1 mol of X produces 1 mol of Y and 2 moles of Z.

Kps = [Y] [Z]^2

We will call “s” (solubility) the molarity of X

So the molarity of Y+ is also “s” (same number)

And the molarity of Z is “2s” (twice as much)

Kps = s*(2s)^2 = s*4s^2=4s^3

If s is multiplied by 2:

Kps = 4*(2s)^3=4*2^3*s^3=4*8*s^3

So Kps is multiplied by 8.

4 0
4 years ago
Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?
Alina [70]
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.

The Coulomb force between the two balls is:
F= k_e \frac{ q_1 q_2}{r^2}
where k_e=8.99\cdot10^9~N m^2 C^{-2} is the Coulomb's constant, q_1=q_2=29~nC=29\cdot 10^{-9}~C is the intensity of the two charges, and r=5.5~cm=0.055~m is the distance between them.

Substituting these numbers into the equation, we get
F=2.5~10^{-3}~N

The force is repulsive, because the charges have same sign and so they repel each other.
6 0
3 years ago
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