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3 years ago

What were two arguments or lines of evidence in support of the geocentric model?

Physics

1 answer:

Inessa05 [86]3 years ago

7 0

Answer:

Two arguments or lines of evidence in support of the geocentric model are:

Geocentric model: This model describe that the earth is in the center of the universe and all the planets. Moon and the sun are revolved around the earth. This model explained the predominant description.

Heliocentric model: In this model the earth and the sun are consider moving and the sun are in the center of the solar system. And the sun is at the center position where all the planets are revolving around it, being dissimilar to the geocentric model.

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A metal rod is 25.000 cm long at 25.0 degrees Celsius. When heated to 102.0

ser-zykov [4K]

Answer:

The coefficient of linear expansion $\alpha =2.8\times 10^-5$ \°C

Explanation:

Given initial temperature $t_1=25$ °C

And final temperature $t_2=102$ °C

Initial length $l_1=25.000\ cm$

Final length $l_2=25.054\ cm$

We have to find the coefficient of linear expansion

The coefficient of linear expansion is defined as the change in length per unit original length divide by the change in temperature.

$l_2=l_1(1+\alpha (t_2-t_1))\\l_2-l_1=\alpha l_1(t_2-t_1)\\25.054-25.000=25.000(\alpha (102-25))\\0.054=\alpha\times 25(77)\\0.054=\alpha\times1925\\\alpha =\frac{0.054}{1925}=0.000028\C\\\alpha =2.8\times 10^-5$

So, $\alpha =2.8\times 10^-5$ \°C

4 0

3 years ago

Why are Substances used as perfumes are usually in a liquid state

tester [92]

Answer:

Perfume is a mixture of fragrant oils in an ethanol/water solvent. The ethanol/water mixture, which is volatile, evaporates from the droplets within a few seconds, leaving behind a droplet of the fragrant compounds in the perfume. These compounds will also eventually evaporate to form a vapor of the fragrant molecules

8 0

2 years ago

Which instrument is used in submarine to see the objects above sea level ?

svetoff [14.1K]

Periscope i believe but i may be wrong.

8 0

3 years ago

Read 2 more answers

A particle of mass m= 2.5 kg has velocity of v = 2 i m/s, when it is at the origin (0,0). Determine the z- component of the angu

melomori [17]

Answer:

please read the answer below

Explanation:

The angular momentum is given by

$|\vec{L}|=|\vec{r}\ X \ \vec{p}|=m(rvsin\theta)$

By taking into account the angles between the vectors r and v in each case we obtain:

v=(2,0)

r=(0,1)

angle = 90°

$L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}$

r=(0,-1)

angle = 90°

$L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}$

r=(1,0)

angle = 0°

r and v are parallel

L = 0kgm/s

r=(-1,0)

angle = 180°

r and v are parallel

L = 0kgm/s

r=(1,1)

angle = 45°

$L = (2.5kg)(2\frac{m}{s})(\sqrt{2})sin45\°=5kg\frac{m}{s}$

r=(-1,1)

angle = 45°

the same as e):

L = 5kgm/s

r=(-1,-1)

angle = 135°

$L=(2.5kg)(2\frac{m}{s})(\sqrt{2})sin135\°=5kg\frac{m}{s}$

r=(1,-1)

angle = 135°

the same as g):

L = 5kgm/s

hope this helps!!

4 0

4 years ago

A box weighs 100N and its base area of 2 m2. What pressure does it exert on the ground?

kotegsom [21]

Answer:

P = F/S = 100/2 =50 (N/m2)

5 0

3 years ago