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almond37 [142]
2 years ago
14

when 57.0 g copper are reacted with silver nitrate solution, 138g of silver are obtained. what is the percent yield of silver ob

tained
Chemistry
1 answer:
maks197457 [2]2 years ago
5 0

Answer:

86.96

Explanation:

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Describe uses of H2S as analytical regent
konstantin123 [22]

Answer:

Hydrogen sulfide is used primarily to produce sulfuric acid and sulfur. It is also used to create a variety of inorganic sulfides used to create pesticides, leather, dyes, and pharmaceuticals. Hydrogen sulfide is used to produce heavy water for nuclear power plants (like CANDU reactors specifically).

Explanation:

Sana Po it's help

8 0
3 years ago
explain what happens if high pressure is implemented on the equilibrium reaction . State your observations for both rate of reac
amm1812
The equilibrium position will shift in order to counterbalance the change. That means the equilibrium position will shift, lowering the pressure once more.... When the pressure on a gas reaction is increased, the equilibrium moves to the side with fewer molecules.
8 0
2 years ago
What is the kinetic energy of a 25 kg object moving at a velocity of 2.5 m/s?
vovangra [49]

Answer:

<h2>78.13 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 25 \times  {2.5}^{2}  \\  = 12.5 \times 6.25 \\  = 78.125 \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>78.13 J</h3>

Hope this helps you

6 0
3 years ago
What is the percent by mass of the solution formed when 5.0 g of solute is dissolved in 40. g of water
d1i1m1o1n [39]

Answer:

2

Explanation:

so let say 5.0/100×40

that is 2

thank you please follow me

7 0
3 years ago
Calculate the pH of a 0.10 M HCN solution that is 0.0070% ionized.
Anastaziya [24]

Answer:

D) 5.15

Explanation:

Step 1: Write the equation for the dissociation of HCN

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

Step 2: Calculate [H⁺] at equilibrium

The percent of ionization (α%) is equal to the concentration of one ion at the equilibrium divided by the initial concentration of the acid times 100%.

α% = [H⁺]eq / [HCN]₀ × 100%

[H⁺]eq = α%/100% × [HCN]₀

[H⁺]eq = 0.0070%/100% × 0.10 M

[H⁺]eq = 7.0 × 10⁻⁶ M

Step 3: Calculate the pH

pH = -log [H⁺] = -log 7.0 × 10⁻⁶ = 5.15

7 0
3 years ago
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