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Mandarinka [93]
3 years ago
11

Find the common difference between the terms of the following arithmetic sequence.

Mathematics
2 answers:
Deffense [45]3 years ago
5 0
B.4
''''''''''''''''''''''''''''
Reika [66]3 years ago
5 0
The common difference is "B.4" 
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I have Warnnnnnnnnn <br>Known<br>2, 8, 14, 20<br><br>Determine the term - 1000 ?​
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<h2>{\green {\boxed {\colorbox {black} {\green {King\:Brainly01}}}}} </h2>

\:

◇◆□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□◆◇

Un = a + ( n - 1 ) b

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4 0
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Read 2 more answers
In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha
lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement,                         Reason

1. \overline{DE} \parallel \overline{AC},                           Given

2. \overline {AB} is a transversal ,         Conclusion from statement 1.

We note that ∠BDE  and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC,                 Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B,                           Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE,          Angle Angle Similarity Postulate

6. BD/BA = BE/BC,      Converse of the Side-Side-Side Similarity Theorem

5 0
3 years ago
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