a) Fraction Notation - 50/100 (1/2 Simplified)
Decimal Notation - 0.50
b) Depends on how many cattle they have, but they sold have of it so 1/2 again?
This Should Be Right?
C 28.84 just multiply 38.45 by .25 then you should get 9.6125 you subtract 38.45 by 9.6125 and get 28.84
9514 1404 393
Answer:
- y -9 = 2(x -1) . . . point-slope form
- y = 2x +7 . . . . slope-intercept form
- 2x -y = -7 . . . . standard form
Step-by-step explanation:
Perhaps you want the equation of the line that goes through these two points.
The slope of the line can be found using the formula ...
m = (y2 -y1)/(x2 -x1)
m = (9 -3)/(1 -(-2)) = 6/3 = 2
We can use one of the points to write the equation in point-slope form:
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
For slope 2 and point (1, 9) the equation is ...
y -9 = 2(x -1) . . . . equation in point-slope form
__
We can eliminate parentheses and get y by itself to put the equation into slope-intercept form.
y -9 = 2x -2
y = 2x +7 . . . . . . equation in slope-intercept form
__
With a little further rearranging, we can put this into standard form. We can get that by adding -7-y to both sides of the equation.
2x -y = -7 . . . . . equation in standard form
Answer:
Option (2).
Step-by-step explanation:
Let f(x) and g(x) are the two functions with domain A and B.
Then (fg)(x) will be the function with domain A∩B
(fg)(x) = f(x)g(x) Domain : A∩B
In this question two functions are,
c(x) =
and d(x) = (x + 3)
Domain : (x - 2) > 0 ⇒ x > 2
and (x - 2) < 0 ⇒ x < 2
Or domain of (cd)(x) will be C = (-∞, 2)∪(2, ∞).
Similarly, d(x) = x + 3
Domain : All real numbers
: D = (-∞, ∞)
(cd)(x) = c(x)d(x)
= 
Domain of (cd)(x) will be,
Domain : C∩D = (-∞, 2)∪(2, ∞) ∩ (-∞, ∞)
: (-∞, 2) ∩ (2, ∞)
Therefore, domain of (cd)(x) will be all real values except 2.
Option (2) will be the answer.
A)
Let's pick point (4,4) and point (2,2). If you divide the new point by the old point you will see that both the x-value and the y-value were multiplied by 2 to gt the new x-value and new y- value. So the scale factor is 2.
The perimeter of the first square can be found by subtracting the x-values from two points to get the length of one side and then multiply the result by 4 to get the perimeter of the whole square.
2-(-2)=4
The length of one side of the first square is 4. (I just subtracted the x-values.)
4 times 4 = 16.
The perimeter of the first square is 16.
Similarly, 4-(-4)=8 and 8 times 4 = 32.
The perimeter of the second square is 32.
b)
Let's pick point (6,6) and point (3,3). If you divide the new point by the old point you will see that both the x-value and the y-value were multiplied by 2 to gt the new x-value and new y- value. So the scale factor is 2.
The perimeter of the first square can be found by subtracting the x-values from two points to get the length of one side and then multiply the result by 4 to get the perimeter of the whole square.
3-(-3)=6
6 times 4 = 24.
The perimeter of the first square is 24.
Similarly, 6-(-6)=12 and 12 times 4 =48.
The perimeter of the second square is 48.
c)
If a figure is dilated to a scale factor of 2 then the perimeter of the figure will also be doubled.