I think the answer is osmosis
The vertical component of velocity is zero
Answer:
the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions = 49.73 J/K.
Explanation:
3Fe2O3(s) + H2(g)-----------2Fe3O4(s) + H2O(g)
∆S°rxn = n x sum of ∆S° products - n x sum of ∆S° reactants
∆S°rxn = [2x∆S°Fe3O4(s) + ∆S°H2O(g)] - [3x∆S°Fe2O3(s) + ∆S°H2(g)]
∆S°rxn = [(2x146.44)+(188.72)] - [(3x87.40)+(130.59)] J/K
∆S°rxn = (481.6 - 392.79) J/K =88.81J/K.
For 3 moles of Fe2O3 react, ∆S° =88.81 J/K,
then for 1.68 moles Fe2O3 react, ∆S° = (1.68 mol x 88.81 J/K)/(3 mol) = 49.73 J/K the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions.
Answer:
Nature versus nurture is a long-standing debate in biology about the balance between two competing factors which determine fate: environment and genetics. The alliterative expression "nature and nurture"
Answer:
77460 g
Explanation:
To solve this problem first we<u> convert molecules into moles</u>, using <em>Avogadro's number</em>:
3.47x10²⁶ molecules ÷ 6.023x10²³ molecules/mol = 576.12 moles
Then we <u>convert 576.12 CuCl₂ moles into grams</u>, using its<em> molar mass</em>:
576.12 mol * 134.45 g/mol = 77460 g
So the answer is 77460 g, or 77.46 kg.
