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2 years ago

A sample of a substance has these characteristics:

Chemistry

2 answers:

Marizza181 [45]2 years ago

8 0

Answer:

an ionic compound

Explanation:

MArishka [77]2 years ago

6 0

<span>Those characteristic belong to an ionic compountd. Ionic compounds have strong bonds between their atoms (ionic bond is the strongest molecular bond) which conferes this kind of compounds high melting point, wich 9811 K is. Ionic compounds do not transmit current, because they do not have free electrons, like metals do, then they are poor conductors as solid. Ionic compounds dissolve in water into ions which are charges that can move, becoming then good conductors. The structure of ionic compound is a net of cristals which make them hard and brittle. Then, the answer i s option (4) an ionic compound.</span>

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Is cotton a synthetic material or a natural material? and why not

Svet_ta [14]

Answer:

Natural

Explanation:

Because synthetics are man made but cotton is plant based

6 0

3 years ago

Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s

Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, $2.67\times 10^2mol/L$

Explanation :

As we know that,

$C_{O_2}=k_H\times p_{O_2}$

where,

$C_{O_2}$ = molar solubility of $O_2$ = ?

$p_{O_2}$ = partial pressure of $O_2$ = 0.2 atm = 1.97×10⁻⁶ Pa

$k_H$ = Henry's law constant = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

$C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)$

$C_{O_2}=8.55\times 10^3g/L$

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = $\frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L$

Therefore, the molar concentration of oxygen is, $2.67\times 10^2mol/L$

8 0

3 years ago

Complete combustion of 2.60 g of a hydrocarbon produced 8.46 g of co2 and 2.60 g of h2o. what is the empirical formula for the h

zubka84 [21]

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.
Hence, in this case the mass of carbon in 8.46 g of CO2:
(12/44) × 8.46 = 2.3073 g
1 mole of water contains 18 g, out of which 2 g is hydrogen;
Therefore, 2.6 g of water contains;
(2/18) × 2.6 = 0.2889 g of hydrogen.
Therefore, with the amount of carbon and hydrogen from the hydrocarbon we can calculate the empirical formula.
We first calculate the number of moles of each,
Carbon = 2.3073/12 = 0.1923 moles
Hydrogen = 0.2889/1 = 0.2889 moles
Then, we calculate the ratio of Carbon to hydrogen by dividing with the smallest number value;
Carbon : Hydrogen
0.1923/0.1923 : 0.2889/0.1923
1 : 1.5
(1 : 1.5) 2
= 2 : 3
Hence, the empirical formula of the hydrocarbon is C2H3

5 0

3 years ago

Show the difference in the reactivity of Na,Ca,Mg,Al,Fe,Cu with H2O

Vesnalui [34]

Answer:

Explanation:

Na react with H2O to form NAOH

2 Na+2H2O....................2NAOH + H2

Ca react with water and form calcium hydroxide

Ca + 2H2O........................Ca(OH)2

Mg react with water and form Magnesium hydroxide

Mg +2H2O .........................Mg(OH)2 however this coating of mg(oh)2 prevent it from further reaction

Fe react with water and form ferric hydride

3Fe +H2O.......................2 FeH +FeO

copper do not react with water

7 0

3 years ago

What element has three electrons in its 5d sublevel?

Sever21 [200]

C. Ta
Tantalum is an element with an atomic number of 63 and its electronic configuration is:
[Xe] 4f¹⁴ 5d³ 6s²

7 0

3 years ago