Answer:
E) we will use t- distribution because is un-known,n<30
the confidence interval is (0.0338,0.0392)
Step-by-step explanation:
<u>Step:-1</u>
Given sample size is n = 23<30 mortgage institutions
The mean interest rate 'x' = 0.0365
The standard deviation 'S' = 0.0046
the degree of freedom = n-1 = 23-1=22
99% of confidence intervals
(from tabulated value).





using calculator

Confidence interval is


the mean value is lies between in this confidence interval
(0.0338,0.0392).
<u>Answer:-</u>
<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>
<em>Answer:</em>
<em>n = 12</em>
<em>Step-by-step explanation:</em>
<em>85%×n = 10.2</em>
<em>85n/100 = 10.2</em>
<em>85n = 1020</em>
<em>n = 1020 : 85</em>
<em>n = 12</em>
Answer:
20,820
Step-by-step explanation:
Answer:
2/3
Step-by-step explanation:
Reduce the fraction 18/27 into its lowest terms
since both 18 and 27 are divisible by 9, divide both terms by 9
18/9 = 2
27/9 = 3
18/27 reduced to lowest terms is 2/3
Answer:
If one −5s−7(8s−1): -61s+7
If two −5s−7(8s−1): -112s+14
Step-by-step explanation:
-5s-7(8s-1)
Multiply -7 onto 8s and -1:
-5s-56s+7
add -5s and -56s:
-61s+7
−5s−7(8s−1)−5s−7(8s−1)
Multiply both -7 to 8s and -1
-5s-56s+7-5s-56s+7
add:
-112s+14