It loses it's fuel supply from the water and begins to weaken
Answer:
it is a the answer is a btw
Explanation:
Answer:
47.8rad/s
Explanation:
For energy to be conserved.
The potential energy sustain by the object would be equal to K.E
P.E = m× g× h = 2 × 9.81× 3.5= 68.67J
Now K.E = 1/2 × I × (w1^2 - w0^2)
I = 2/3 × M × R2
= 2/3 × 2 × (0.23)^2= 0.0705
Hence
W1 = final angular velocity
Wo = initial angular velocity
From P.E = K.E we have;
68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)
(w1^2 - w0^2) = 1948.09
W1^2 = 1948.09 + (18.3^2)
W1^2=2282.98
W1 = √2282.98
=47.78rad/s
= 47.8rad/s to 1 decimal place.
Answer
rate of current = (1/x) mph
Explanation
let the distance from <span>Greentown to Glenavon be y miles and the rate of current be x mph.
y = (15+x)g
y = 15g+gx .........................................(1)
The distance from </span><span>Glenavon to Cambria = (y-2)
y-2 =(15-x)g
y-2 = 15g-gx
y = 15g - gx + 2 ....................... (2)
equation equation (1) and (2)
15g + gx = 15g - gx + 2
2gx = 2
dividing by 2g both sides we get,
x = 1/2g mph
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