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storchak [24]
3 years ago
10

The speed of a sound wave in seawater is approximately 1500m/s. If the wave is transmitted at 10ms-1, what is its wavelength? An

swer in cm
Physics
1 answer:
serg [7]3 years ago
7 0
The wave travels at the speed of sound in water: v=1500 m/s.

The frequency of the wave is 
10 ms^{-1} = 10000 s^{-1} = 10000 Hz

so we can find its wavelength \lambda by using the basic relationship between frequency, wavelength and speed of the wave:
\lambda= \frac{v}{f}= \frac{1500 m/s}{10000 Hz}=0.150 m = 15 cm
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5. How are humans affecting global climate change?
andreyandreev [35.5K]

Answer:

Due to the generation of carbon dioxide

Explanation:

Climate change occurs due to global warming generated by greenhouse gases. Carbon dioxide is the gas that does not leave or allow solar radiation from the sun to rise from the Earth's surface, increasing the average temperature of the planet.

Burning fossil fuels for energy generation such as coal is another source of carbon dioxide generation. The generation of energy should be directed towards the production of renewable energies, using sources such as solar and wind energy.

5 0
3 years ago
The amount of energy which is transported past a given area of the medium per unit of time is known as the ________ of the sound
Aliun [14]
The term that describes the amount of energy transported past a given area of the medium per unit time would be "intensity." In addition, the formula for computing intensity would be:

Intensity = Energy / (Time * Area)

It can be implied that the wave would be more intense when its energy transfer rate gets increased and vibration amplitudes also increases.
6 0
3 years ago
A block weighting 400kg rests on a horizontal surface and support on top of it another block of weight 100kg placed on the top o
masha68 [24]

The horizontal force applied to the block is approximately 1,420.84 N

The known parameters;

The mass of the block, w₁ = 400 kg

The orientation of the surface on which the block rest, w₁ = Horizontal

The mass of the block placed on top of the 400 kg block, w₂ = 100 kg

The length of the string to which the block w₂ is attached, l = 6 m

The coefficient of friction between the surface, μ = 0.25

The state of the system of blocks and applied force = Equilibrium

Strategy;

Calculate the forces acting on the blocks and string

The weight of the block, W₁ = 400 kg × 9.81 m/s² = 3,924 N

The weight of the block, W₂ = 100 kg × 9.81 m/s² = 981 N

Let <em>T</em> represent the tension in the string

The upward force from the string = T × sin(θ)

sin(θ) = √(6² - 5²)/6

Therefore;

The upward force from the string = T×√(6² - 5²)/6

The frictional force = (W₂ - The upward force from the string) × μ

The frictional force, F_{f2} = (981 - T×√(6² - 5²)/6) × 0.25

The tension in the string, T = F_{f2} × cos(θ)

∴ T = (981 - T×√(6² - 5²)/6) × 0.25 × 5/6

Solving, we get;

T = \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8} \approx 183.27

Frictional \ force, F_{f2} = \left (981 -  \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8}  \times \dfrac{\sqrt{6^2 - 5^2} }{6} \times  0.25 \right) \approx 219.92

The frictional force on the block W₂, F_{f2} ≈ 219.92 N

Therefore;

The force acting the block w₁, due to w₂ F_{w2} = 219.92/0.25 ≈ 879.68

The total normal force acting on the ground, N = W₁ + \mathbf{F_{w2}}

The frictional force from the ground, \mathbf{F_{f1}} = N×μ + \mathbf{F_{f2}} = P

Where;

P = The horizontal force applied to the block

P = (W₁ + \mathbf{F_{w2}}) × μ + \mathbf{F_{f2}}

Therefore;

P = (3,924 + 879.68) × 0.25 + 219.92 ≈ 1,420.84

The horizontal force applied to the block, P ≈ 1,420.84 N

Learn more about friction force here;

brainly.com/question/18038995

3 0
3 years ago
Pls help ASAP now! This is physical science
const2013 [10]

Option A is correct answer

6 0
3 years ago
Read 2 more answers
Connelly cuts a solid object in half. What happens to the mass, volume, and density of the object that Connelly cuts? A)The mass
amm1812
I think the correct answer would be D. After cutting the solid object in half, the mass and volume are both divided by two, but the density remains the same. The mass and volume would change accordingly to satisfy the law of conservation of mass which states that mass cannot be created or destroyed. So, after dividing the object the sum of the mass of the two parts should be equal to the original mass of the object. This would also be the same for the volume of the objects. Density is the ratio of mass and volume and, since the mass and volume change accordingly, the value of the density would still be the same regardless of the object being divided.
3 0
3 years ago
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