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sukhopar [10]
3 years ago
15

Rory uses a force of 25 N to lift her grocery bag while doing 50 J of work. How far did she lift the

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

W=Fd \\ 50 = 25d \\ d =  \frac{50}{25}  \\  \color{yellow} \boxed{d = 2m}

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A sperm whale can accelerate at about 0.0800 m/s 2 0.0800 m/s 2 when swimming on the surface of the ocean. How far will a sperm
Norma-Jean [14]

Answer:

26.64 m

Explanation:

Given the following :

Acceleration at ocean surface = 0.0800 m/s²

Distance covered if initial speed = 0.700 m/s and accelerates to a speed of 2.18m/s

Using the equation :

v² = u² + 2as

Where ;

v = final velocity ; u = initial velocity ; a = acceleration ; s = distance covered

Therefore,

v² = u² + 2as

2.18² = 0.7² + (2 × 0.08 × s)

4.7524 = 0.49 + 0.16s

4.7524 - 0.49 = 0.16s

4.2624 = 0.16s

s = 4.2624 / 0.16

s = 26.64 m

7 0
3 years ago
Which is true about atoms?
tiny-mole [99]

Answer:

A

Explanation:

6 0
3 years ago
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Which of the following is NOT a characteristic of a planet?
stepladder [879]

Answer:

1: body of significant size

Explanation:

Hopefully this helps!

5 0
3 years ago
The speed of a certain proton is 350 km/s. If the uncertainty in its momentum is 0.100%, what is the necessary uncertainty in it
Evgesh-ka [11]

Answer:

\Delta x = 1.807 \times 10^{-10}m

Explanation:

mass of proton, m = 1.67 x 10^-27 kg

speed of proton, v = 350 km/s = 350,000 m/s

Momentum of proton, p = mass x speed

p =  1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s

uncertainty in momentum, Δp = 0.1 % of p

Δp = \frac{0.1\times 5.845 \times 10^{-22}}{100}=5.845 \times 10^{-25}

According to the principle

\Delta x\times \Delta p \geq  \frac{h}{2\pi }

where, Δx be the uncertainty in position

\Delta x\times 5.845 \times 10^{-25}=  \frac{6.634 \times 10^{-34}}{2\times 3.14}

\Delta x = 1.807 \times 10^{-10}m

5 0
3 years ago
A 66-kg woman cheats on her diet and eats a 625-Calorie (625 kcal) jelly doughnut for breakfast. (a) How many joules of energy a
xenn [34]

Answer:

a) E=2.616\times 10^6 \textup{ J}

b) 26966 stairs

c) 7012 stairs

Explanation:

Given:

Mass of the woman =  64 kg

Energy intake =  459 kcal.

(a)Noe, the energy equivalent of one jelly doughnut can be calculated as

E = 459\times 10^3 \ cal

E = (625\times 10^3 \textup{ cal})(\frac{ 4.186 \textup{ J}}{1\textup{ cal}}) = 2616250\textup{ J}

or

E=2.616\times 10^6 \textup{ J}

(b) The number of steps climbed by the woman to consume one jelly doughnut of energy can be calculated as:

The gravitational potential energy to climb each step of stair case is given as:

W = mgh

where,

m = mass

g = acceleration due to gravity

h = height up to which mass is moved  

Now, Total work done to climb the n number of steps is,

            W =n(mgh)

where, n is the number of steps on stairs

on rearrange, we get,

n = \frac{W}{mgh}

or

n = \frac{2616250 \textup{ J}}{(66\textup{ kg})(9.8 \textup{ m/s}^2)(0.15\textup{ m})}

or

n = 26966.08 ≅ 26966 stairs

(c) The number of steps climbs by woman when the body is 26% efficient:

n = \frac{(0.26)W}{mgh}

Therefore, number of steps:

n = \frac{(0.26)(2616250) \textup{ J}}{(66\textup{ kg})(9.8 \textup{ m/s}^2)(0.15\textup{ m})}

or

n = 7011.18 ≅ 7012 stairs

4 0
3 years ago
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