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3 years ago

Rory uses a force of 25 N to lift her grocery bag while doing 50 J of work. How far did she lift the

Physics

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Answer:

$W=Fd \\ 50 = 25d \\ d = \frac{50}{25} \\ \color{yellow} \boxed{d = 2m}$

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A particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity

klasskru [66]

Explanation:

It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion

Case I

s=ut+

10=5u+

a(5)

20=10u+25a

4=2u+5a..............(1)

Case 2

In next 3s the particle covers more 10m distance. So

20=8u+

a(8)

5=2u+8a.........(2)

On solving equation (1) and (2)

4=2u+5a

5=2u+8a

m/s

Put the value of a in equation (1)

m/s

Now to find distance in next 10 s. total time will be 10s

×10+

×(10)

s=28.33m

Distance travelled in next 2 sec

s=28.33−20=8.33m

4 0

3 years ago

Read 2 more answers

A double insulated drill ____. A. has two ground wires to insure proper grounding B. generally has a plastic case with the elect

Len [333]

Answer:

Option B is correct.

A double insulated drill generally has a plastic case with the electrical connections and motor insulated within the tool

Explanation:

A double insulated drill's design in real life has plastic casing as the insulator & it wouldn't be a drill without its motor now, would it!?

8 0

3 years ago

Describe a situation that includes no less than four charges of any magnitude, but they combine so that another location, p, has

Degger [83]

Answer:

Four charges of equal magnitude sitting at the vertices of a square

Explanation:

We can arrive at such a situation by thinking of a simple example first, a configuration of two charges. The force acting on the middle point of a straight line joining the two points(charges) will be zero. That is, the net Electric field will be zero as they cancel out being equal in magnitude and opposite in direction.

Now, we can extend this idea to a square having charge q at each vertex. If we put 'p' at the geometric center, we can see that the Electric fields along the diagonals cancel out due to the charges at the diagonally opposite vertices(refer to the figure attached). Actually, the only requirement is that the diagonally opposite charges are equal.

We can further take this to 3 dimensions. Consider a cube having charges of equal magnitude at each vertex. In this case, the point 'p' will yet again be the geometric center as the Electric field due to the diagonally opposite charges will cancel out.