2 years ago

On Derwin farm there is a total of 50 chickens and cows. If there are 118 legs, how

Mathematics

1 answer:

OverLord2011 [107]2 years ago

4 0

<h2><u><em>Answer:</em></u></h2>

Chickens have 2 legs and cows have 4 legs.

Let x = # of chickens and let y = # of cows.

2x + 4y = 118

x + y = 50

x= 50 - y

2(50 - y) + 4y =118

100 - 2y + 4y = 118

2y = 18

y = 9

x = 41

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