Answer:
D.
Step-by-step explanation:
Any parabola is modelled by a second-order polynomial, whose standard form is:
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
,
,
- Coefficients, dimensionless.
In addition, a system of three linear equations is constructed by using all known inputs:
(-2, 0)
(Eq. 1)
(4, 0)
(Eq. 2)
(0,-16)
(Eq. 3)
Then,
(Eq. 4)
(Eq. 5)
(Eq. 3 in Eqs. 1 - 2)
By Eq. 4 (Eq. 4b)
Then,
(Eq. 4b in Eq. 5)
The remaining coeffcient is:
The function that represents a parabola with zeroes at x = -2 and x = 4 and y-intercept (0,16) is . Thus, the right answer is D.
