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makkiz [27]
2 years ago
12

What allows transgenic salmon to grow in the winter months?

Chemistry
1 answer:
Nitella [24]2 years ago
7 0

Answer:

An aquaculture company called AquaBounty Farms has produced the first transgenic animal intended for human consumption: Atlantic salmon with two donor genes from other fish. The donated genes keep the transgenic salmon growing year-round, instead of taking a winter break, so they reach adult size faster than normal.

Explanation:

hope \: it \: helps \: you

You might be interested in
Please help me! Thank you<br> (Image down bellow)
choli [55]

Answer:

I'm pretty sure it's neutrons the first one

5 0
3 years ago
Read 2 more answers
A standard solution is prepared for the analysis of fluoxymesterone (C20H29FO3), an anabolic steroid. A stock solution is first
VLD [36.1K]

Answer:

The final solution has a concentration of 5.95 * 10^-6 M

Explanation:

<u>Step 1:</u> data given

Mass of fluoxymesterone : 10mg = 0.01g

Molar mass of  fluoxymesterone = 336g/mole

Volume = 500 mL =0.5 L

<u>Step 2:</u> calculate Concentration of  fluoxymesterone

Concentration = mole / volume

⇒ To find the concentration, we first need to find the number of moles

⇒moles fluoxymesterone= mass of fluoxymesterone / Molar mass

0.01g / (336g/mole) = 2.976 *10^-5 mole

C =  2.976 *10^-5 mole / 0.5 L = <u>5.95 * 10 ^-5 M</u>

<u>Step 3:</u> Calculate dilution

⇒ If 10 mL  is diluted to 100 ml then this is a 10x dilution (100 ml /10 ml = 10) so the final solution will be 10 x more dilute.

⇒5.95 * 10^-5 M /10  = 5.95 ^* 10^-6 M

We can control this through the following formula: M1 * V1 = M2 * V2

5.95 *10^-5 * 10 * 10 *^-3 = M2 *0.1 L

M2 = 5.95 * 10^-6 M

6 0
4 years ago
How many molecules of sodium oxide will be created if 275 grams of sodium reacts with excess oxygen?
musickatia [10]

3.6 x 10²⁴molecules

Explanation:

Given parameters:

Mass of Na = 275g

Unknown:

Number of molecules of Na₂O =  

Solution:

Since sodium is the limiting reactant, we first use it to find the number of mole of the Na₂O  and transpose it into finding the number of molecules.

  Given equation:

                     4Na  + O₂  →   2Na₂O

Since the equation is balanced, let us find the number of moles of Na;

 Number of moles = \frac{mass}{molar mass}  = \frac{275}{23} = 11.96moles

From the equation of the reaction;

    4 mole of Na produced  2 moles of Na₂O

   11.96 moles of Na will produce \frac{11.96  x  2}{4}  = 6moles

1 mole of a substance = 6.02 x 10²³ molecules

 6 moles of Na₂O = 6 x 6.02 x 10²³ molecules = 3.6 x 10²⁴molecules

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

5 0
3 years ago
Complete the passage. K (potassium) belongs to group IA of the periodic table, and has 1 valence electron. Br (bromine) belongs
Lelechka [254]

Answer:

See detailed explanation.

Explanation:

Hello.

In this case, since the electron configuration of potassium whose atomic number is 19 turns out:

K^{19}: 1s^2,2s^2,2p^6,3s^2,3p^6,4s^1

We can see that the last level is 4 which has one electron, meaning that potassium has one valence electron. Moreover, since bromine's atomic number is 35, its electron configuration is:

Br^{35}: 1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^5

We can see that the last level is also 4 and it has 2+5 = 7 valence electrons. In such a way, we infer that the valence electrons are computed by the electrons at the outer or last energy level of an element.

Regards.

7 0
4 years ago
Read 2 more answers
How many grams of water are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca
leva [86]

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

                           2HCl     +     Ca(OH)2    →        2H2O    +      CaCl2

MW                   2(36.5)               74                       36 g               111 g

                          73g                

                            1 mol of HCl ----------------  36.5 g

                           2.6 mol           --------------    x

                              x = (2.6 x 36.5) / 1   = 94.9 g

                           1 mol of Ca(OH)2 --------------   74 g

                         1.4 mol                  ---------------   x

                            x = (1.4 x 74) / 1  = 103.6 g

Grams of water

                        73 g of HCl ------------------   36g of H2O

                        94.9 g        -------------------    x

                     x = (94.9 x 36) / 73 = 46.8 g of water

6 0
3 years ago
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