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vredina [299]
3 years ago
6

"a sample of helium gas at 27.0 °c and 4.20 atm pressure is cooled in the same container to a temperature of -73.0 °c. what is t

he new pressure?"
Chemistry
1 answer:
beks73 [17]3 years ago
4 0

Answer: 2.80 Atm

Explanation:

Gay-lussac's law

P1÷T1=P2÷T2

T2·P1÷T1

(200)·(4.20)÷300

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One litre of hydrogen at STP weight 0.09gm of 2 litre of gas at STP weight 2.880gm. Calculate the vapour density and molecular w
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Answer:

we know, at STP ( standard temperature and pressure).

we know, volume of 1 mole of gas = 22.4L

weight of 1 Litre of hydrogen gas = 0.09g

so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.

similarly,

weight of 2L of a gas = 2.88gm

so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g

hence, molecular weight of the gas = 32.256g

vapor density = molecular weight/2

= 32.256/2 = 16.128g

hence, vapor density of the gas is 16.128g.

Explanation:

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Explanation:

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