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3 years ago

6

"a sample of helium gas at 27.0 °c and 4.20 atm pressure is cooled in the same container to a temperature of -73.0 °c. what is t

he new pressure?"

1 answer:

beks73 [17]3 years ago

4 0

Answer: 2.80 Atm

Explanation:

Gay-lussac's law

P1÷T1=P2÷T2

T2·P1÷T1

(200)·(4.20)÷300

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