Answer:
Explanation:
Quantity of heat required by 10 gram of ice initially warm it from -5°C to 0°C:
here;
mass, m = 10 g
specific heat capacity of ice, 
change in temperature, 
Amount of heat required to melt the ice at 0°C:
where, 
we know that no. of moles is = (wt. in gram) 
(molecular mass)
Now, the heat required to bring the water to 70°C from 0°C:
specific heat of water, 
change in temperature, 
Therefore the total heat required to warm 10.0 grams of ice at -5.0°C to a temperature of 70.0°C:
Proprietățile fizice ale mineralelor depind in cea mai mare măsură de compozitie chimică si structura reticulara reprezintă importanta deosebită în recunoașterea mineralelor
Since the temperature is constant, therefore, this problem can be solved based on Boyle's law.
Boyle's law states that: " At constant temperature, the pressure of a certain mass of gas is inversely proportional to its pressure".
This can be written as:
P1V1 = P2V2
where:
P1 is the initial pressure = 1 atm
V1 is the initial volume = 3.6 liters
P2 is the final pressure = 2.5 atm
V2 is the final volume that we need to calculate
Substitute with the givens in the above mentioned equation to get the final volume as follows:
P2V1 = P2V2
1(3.6) = 2.5V2
3.6 = 2.5V2
V2 = 3.6 / 2.5 = 1.44 liters
I think the answer to your question would be D.
Answer: The phase change for A and B respectively is condensation, freezing.
Explanation:
A process in which gaseous state of a substance converts into liquid state is called condensation.
For example, conversion of steam into water.
A process in which liquid state of a substance converts into solid state is called freezing.
For example, conversion of liquid water into ice.
Thus, we can conclude that the phase change for A and B respectively is condensation and freezing.
