Charles Darwin was a Geologist, biologist and is best known for his contributions to science of evolution.
Answer:
0.0042 M is the molarity of tartaric acid in this sample of wine.
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is tartaric acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL](https://tex.z-dn.net/?f=n_1%3D2%5C%5CM_1%3D%3F%5C%5CV_1%3D10.0%2B40.0%20mL%3D50.0%20mL%5C%5Cn_2%3D1%5C%5CM_2%3D0.051%20M%20M%5C%5CV_2%3D8.20%20mL)
Putting values in above equation, we get:
![2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL](https://tex.z-dn.net/?f=2%5Ctimes%20M_1%5Ctimes%2050.0%20mL%3D1%5Ctimes%200.051%20M%5Ctimes%208.20%20mL)
![M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M](https://tex.z-dn.net/?f=M_1%3D%5Cfrac%7B1%5Ctimes%200.051%20M%5Ctimes%208.20%20mL%7D%7B2%5Ctimes%2050.0%20mL%7D%3D0.0042%20M)
0.0042 M is the molarity of tartaric acid in this sample of wine.
Place a 2 in front of the HCl.
This is because the product is yielded to be both H2 and Cl2, diatomic elements. In the reactants side, HCl has no coefficient, but by adding 2, the equation will become balanced.
Hope this helps!