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Molodets [167]
2 years ago
13

What is 10 ÷ 2/5 (show ur work)

Mathematics
1 answer:
SOVA2 [1]2 years ago
7 0

Answer:

25.

The answer is 25

10÷2=5

10÷5=2

so 25

:)

Hope dis helps

Learning with nat~

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Can someone help me with question 1 and 2 please​
klasskru [66]
Question 1)
there’s 180 degrees in a triangle
70 + 70 = 140
180 - 140= 40
A= 40
question 2)
there’s only one line of symmetry, down the middle
5 0
3 years ago
Does the following graph have horizontal or vertical symmetry?
Dvinal [7]
Vertical symetticalt
7 0
3 years ago
Read 2 more answers
Find h(-4 ) given h(x)=3x2 +2x -16​
liubo4ka [24]

Answer:

2x-10

Step-by-step explanation:

3x2+2x-16

6+2x-16

2x-10

4 0
3 years ago
In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat
Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

427 had paid for coaching courses and the remaining 2733 had not.

This means that n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0
3 years ago
There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red
madam [21]

Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =\frac{12}{20}

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =\frac{8}{19}

So, the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag =\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}

Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

3 0
3 years ago
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