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Alexxx [7]
2 years ago
9

In a survey of 92 pet owners, 11 said they own a dog, and 39 said they own a cat. 4 said they own both a

Mathematics
1 answer:
LuckyWell [14K]2 years ago
3 0

Answer:

35 people

Step-by-step explanation:

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Maria is playing a video game. She earns 15 points when she completes level one. Each time she completes a level, she earns twic
andrey2020 [161]

Answer:

She will earn 1,920 points.  PLEASE GIVE BRAINLIEST!!!

Step-by-step explanation:

Level 1 : 15 points   x 2 = level 2

Level 2 : 30 points   x 2 = level 3

Level 3: 60 points    x2 = level 4

Level 4:  120 points   x2 = level 5

Level 5:  240 points   x2 = level 6

Level 6:  480 points  x2 = level 7

Level 7:  960 points  x2 = level 8

Level 8:  1,920 points

8 0
4 years ago
PLEASE HELP you just have to help with a few
vagabundo [1.1K]
<h3><em>Answers:</em></h3><h2 /><h2>1/4 + 2/3 =11/12</h2><h2 /><h2>2/5-1/10= 3/10</h2><h2 /><h2>1/6+1/4=5/12</h2><h2 /><h2>5/8-1/4=3/8</h2><h2 /><h2>7/8-1/2=3/8</h2><h2 /><h2>3/10+4/5=11/10 or 1 1/10</h2><h2 /><h2>5/6-2/5=3/5</h2><h2 /><h2>5/12-1/4=1/6</h2><h2 /><h2>7/16+1/8=9/16</h2><h2 /><h2>11/16+5/8=21/16 or 1 5/16</h2><h2 /><h2>2/7+1/2=11/14</h2><h2 /><h2>4/5+3/4=31/20 or 1 11/20</h2>
3 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
Dmitry_Shevchenko [17]
Answer: x = 20

We know opposite angles are equivalent so we can set both of these expressions equal to each other to solve for x.

3x + 50 = 6x - 10
50 = 3x - 10 (subtract 3x from both sides)
60 = 3x (add 10 to both sides)
20 = x (divide both sides by 3)

8 0
3 years ago
A dependent system of equations is a system with __________.
andre [41]
The same line is written in two different forms
6 0
3 years ago
Solve using the quadratic formula 3x^2+11x+5=0
storchak [24]

Answer:

3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}

Decimal:

(x = -0.53162..., x = -3.13504...)

Step-by-step explanation:

3x^2+11x+5=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}

x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}

The solutions to the quadratic equation are:

x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0
4 years ago
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