ANSWER
The area of square ABCD is

EXPLANATION
The area of square ABCD is the square of the length of one side.
That is the area of ABCD is |AD|²
From Pythagoras theorem,

We can read from the graph that, each box is one unit.
This implies that,



Therefore the area of square ABCD is 25 square units.
The correct answer is option C.
Answer:
Angle ABC =40º.
Step-by-step explanation:
We know that angle ABD = 70º. We also know that angle CBD= 30º . Therefore angle ABD - angle CBD will give us the measurement of angle ABC. 70º - 30º= 40º.
Answer: if the circumference is 76 the area is 38
Step-by-step explanation:
Answer:
x = -4 & It's same side Interior
Step-by-step explanation:
If you have any questions about the way I solved it correctly, don't hesitate to ask me in the comments below ÷)
9514 1404 393
Answer:
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^0 = 1 . . . . for a ≠ 0
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And, it is convenient to know the cubes of small integers:
1³ = 1; 2³ = 8; 3³ = 27; 4³ = 64; 5³ = 125
6³ = 216; 7³ = 343; 8³ = 512; 9³ = 729; 10³ = 1000
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1) p^3 × p^5 = p^-12 × p^y
Equating exponents:
3 + 5 = -12 + y
20 = y . . . . . . . . . . . add 12
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2) 64 × 4^5 = 4^3 × 4^5 = 4^(3+5) = 4^8
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3) 10^x = 1 = 10^0
x = 0