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3 years ago

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to Question 1 options:

Chemistry

1 answer:

professor190 [17]3 years ago

3 0

Answer:

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.

Explanation:

Boyle’s Law : At constant temperature, the volume of a given quantity of a gas varies inversely with its pressure.

It is clear from the data that V ∝ 1/P.

Also, PV = constant.

So, for two different values of both P and V:

∴ P₁V₁ = P₂V₂.

∵ V₂ = 1/3V₁

∴ P₂ = P₁V₁/V₂ = P₁V₁/(1/3V₁) = 3P₁.

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uranmaximum [27]

Answer:

<h3>The answer is 1.12 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

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We have

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vesna_86 [32]

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Answer:

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Explanation:

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