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Archy [21]
3 years ago
15

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to Question 1 options:

Chemistry
1 answer:
professor190 [17]3 years ago
3 0

Answer:

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.

Explanation:

  • Boyle’s Law : At constant temperature, the  volume of a given quantity of a gas  varies inversely with its pressure.
  • It is clear from the data that V ∝ 1/P.
  • Also, PV = constant.

So, for two different values of both P and V:

∴ P₁V₁ = P₂V₂.

∵ V₂ = 1/3V₁

∴ P₂ = P₁V₁/V₂ = P₁V₁/(1/3V₁) = 3P₁.

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PLEASE HELP!!!! WILL MARK BRAINLIEST!!!! A rigid steel container with a volume of 30 L is filled with oxygen to a pressure of 9.
GuDViN [60]

Answer:

12 atm

Explanation:

First, let us convert Celcius into Kelvin: 28.0 °C = 301.15 K and 129.0 °C = 402.15 K

For this question we must employ the Combined Gas Law: \frac{P_1V_1}{P_2V_2}=\frac{n_1RT_1}{n_2RT_2}, where P_1 is the initial pressure and P_2 is the new pressure.

We know that intitially, P=9 atm, V=30 L, and T=301.15K. From our problem, only temperature and pressure changes, while the number of moles, volume and the gas constant, R, stay the same, so they are irrelevant.

Thus, the filled out Combined Gas Law would be:

\frac{9 atm}{P_2}=\frac{301.15K}{402.15K}, where the volume, moles of gas, and R are cancelled out.

We can manipulate this equation to derive the new pressure. We find that

9atm≈0.74885P_2.  

This means that

P_2≈9/0.74885≈12 atm

4 0
3 years ago
The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g
ra1l [238]

Answer:

1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.

Explanation:

1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

6.97g.\frac{1mol}{22.98g} .\frac{-369kJ}{2mol} =-56.0kJ

2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).

CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g)  ΔH = 2.80 kJ

The enthalpy of the reaction is positive, which means that 2.80 kJ of energy are absorbed per mole of carbon monoxide. The energy evolved for 10.4 g of CO (molar mass 28.01 g/mol) is:

10.4g.\frac{1mol}{28.01g} .\frac{2.80kJ}{mol} =1.04kJ

3 0
4 years ago
An airplane travels with a constant velocity of 210 m/s and in the upper atmosphere where the plane is traveling there is a wind
kolezko [41]

Answer:

hello your question is incomplete the options are missing

Determine the resultant velocity for the plane when it is travelling

i) To the east

ii) To the west

answer :i)  270 i

             ii)  -150 i

Explanation:

velocity of Airplane = 210 m/s

wind velocity = 60 m/s to the east

The resultant velocity for the plane when it is travelling  

let the velocity of the wind = V2

           velocity of the plane = v1

i) The resultant velocity for the plane when travelling to the east

Vr = V2 i  + V1 i

Vr= 60i + 210i  = 270i

ii) resultant velocity when the plane is travelling to the west

Vr = - V1 i + V2i

     = -210i  + 60 i = -150 i  

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3 years ago
How Mendeleev's systematic approach resulted in the development of his Periodic Table of elements.
tensa zangetsu [6.8K]
I just wanna know what does that even mean
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A rooster laid an egg on top of the barn roof. Which way did it roll?
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