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zhenek [66]
2 years ago
9

Please help with this asappppppppll

Mathematics
1 answer:
Alenkinab [10]2 years ago
7 0

We are given with a circle and we need to find the <em>equation of the circle</em> , but first let's recall that , the equation of a circle with radius<em> 'r'</em> and centre at <em>(h,k) </em>is given by {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}

Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here <em>(h,k) = (0,0)</em> .Which means that the centre is located at the point whose coordinates are<em> (0,0)</em> which is also known as origin . Now , finding the equation of the circle :-

{:\implies \quad \sf (x-0)^{2}+(y-0)^{2}=(9)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{x^{2}+y^{2}=81}}}

<em>This is the required equation of Circle</em>

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