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Bad White [126]
2 years ago
10

What are the zeros of f(x)=x^2+2x-80

Mathematics
1 answer:
andrezito [222]2 years ago
3 0

Answer:

The zeros are 8 and -10, all u have to do is substitute x for those values, factor it, or graph it.

Step-by-step explanation:

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Among all pairs of numbers whose difference is 20, find a pair whose product is as small as possible. what is the minimum produc
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Step-by-step explanation:

Let the smaller number be x.

Then the larger number is x + 20.

The product is x(x + 20).

Now you can write the function

y = x(x + 20)

y = x^2 + 20x

Take the first derivative of y with respect to x.

y' = 2x + 20

Set the first derivative equal to zero to find the x value for the minimum value of the function.

2x + 20 = 0

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x = -10

The minimum value of the function occurs at x = -10. -10 is one of the two numbers.

y = x^2 + 20x

For x = -10,

y = (-10)^2 + 20(-10)

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y = -100

The minimum value of the product is -100.

x = -10

x + 20 = -10 + 20 = 10

The numbers are -10 and 10.

If you have not learned derivatives yet, then plot the function

y = x^2 + 20x

Now look at the graph and find the minimum y value and the x value at which it occurs.

The minimum y value is -100. That is the minimum product you are looking for.

The x value of the minimum function value is x = -10.

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The numbers are -10 and 10.

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4 years ago
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