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Pachacha [2.7K]
3 years ago
12

The combustion of ethene, C2H4 , occurs via the reaction C2H4(g)+3O2(g)→2CO2(g)+2H2O(g) with heat of formation values given by t

he following table: Substance ΔH∘f ( kJ/mol ) C2H4 (g) 52.47 CO2(g) − 393.5 H2O(g) − 241.8 Calculate the enthalpy for the combustion of 1 mole of ethene.
Chemistry
1 answer:
tekilochka [14]3 years ago
3 0
The combustion of ethene, C2H4 , occurs via the reaction C2H4(g)+3O2(g)→2CO2(g)+2H2O(g) with heat of formation values given by the following table: ...
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From the question given above, the following data were obtained:

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\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

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298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

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