What is the reaction type 2 Mgl2+ Mn(SO3)2 → 2 MgSO3 + Mnl4

What happens to the energy of an electron if it moves from one energy level to another

Zigmanuir [339]

Answer:

The energy levels in an atom are similar to the rungs of a ladder, but they get closer together as they get farther from the nucleus. For an electron to move from one energy level to the next higher level, it must gain the right amount of energy. If less than that amount is available, the electron stays where it is.

Explanation:

Hope this helped! Goodluck on your test or whatever you're doing! Stay safe ♥♥♥

6 0

3 years ago

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Name this compound Cr2(CO3)3

kiruha [24]

Answer:

Molecular Weight

Explanation:

Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

5 0

3 years ago

Who wants a metal?

tiny-mole [99]

Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?

A. Both have the same molar mass.

B. Both have the same number of ions.

C. Both are made up of 6.02 mc014-1 1023 molecules.

D. Both are made up of 6.02 mc014-2 1023 formula units.

The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D

8 0

3 years ago

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Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decoxide and water, as

erica [24]

Answer: The amount of $P_4O_{10}$ formed is 469.8 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of phosphine = 225 g

Molar mass of phosphine = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of phosphine}=\frac{225g}{34g/mol}=6.62mol$

The given chemical reaction follows:

$4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)$

Assuming that oxygen gas is present in excess, it is considered as an excess reagent.

Phosphine is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of phosphine produces 1 mole of $P_4O_{10}$

So, 6.62 moles of phosphine will produce = $\frac{1}{4}\times 6.62=1.655mol$ of $P_4O_{10}$

Now, calculating the mass of $P_4O_{10}$ by using equation 1:

Molar mass of $P_4O_{10}$ = 283.9 g/mol

Moles of $P_4O_{10}$ = 1.655 moles

Putting values in equation 1, we get:

$1.655mol=\frac{\text{Mass of }P_4O_{10}}{283.9g/mol}\\\\\text{Mass of }P_4O_{10}=(1.655mol\times 283.9g/mol)=469.8g$

Hence, the amount of $P_4O_{10}$ formed is 469.8 grams.

8 0

3 years ago

Help please chemistry question

Gemiola [76]

Answer:

D. $K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}$

Explanation:

The general form of an equilibrium constant expression is

$K = \frac{[\text{Products}]}{[\text{Reactants}]}$

In the equilibrium

HNO₂ ⇌ H⁺ + NO₂⁻

The products are H⁺ and NO₂⁻, and the reactant is HNO₂.

∴ $K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}$

3 0

3 years ago