In order to determine the mole ratio, you need to begin with a balanced chemical equation.
The mixture should be
Heterogeneous
Explanation:
<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u> Diverse in character or content.
Answer:
C. Refining
Explanation:
Refining process removes elements from a substance
Answer:
17.5609grams
Explanation:
According to the question, a sample of mass 6.814 grams is added to another sample weighing 0.08753 grams i.e.
= 6.814 + 0.08753
= 6.90153 grams
The result of this mixture i.e. 6.90153 grams is divided into three equal parts i.e.
= 6.90153 ÷ 3
= 2.30051 grams
This means that each equal part weighs 2.30051 grams
One of the yield (2.30051 grams) is multiplied by 7.6335 times i.e.
= 2.30051 × 7.6335
= 17.56094309
Hence, the final mass is 17.5609grams
