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Anon25 [30]
3 years ago
15

An individual has 3 different email accounts. Most of her messages, in fact 60% come into account #1, whereas 30%come into accou

nt #2, and the remaining 10% into account #3. Of the messages into account #1, only 1% are spam, whereas the corresponding percentages for account #2 and #3 are 3% and 5%, respectively. What is the probability that a randomly selected message is spam?
Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

the probability is 0.02 (2%)

Step-by-step explanation:

defining the event S= the message is spam , then the probability is

P(S) = probability that a randomly selected message comes from account #1 * probability that the message is spam given that the message is from account #1 + probability that a randomly selected message comes from account #2 * probability that the message is spam given that the message is from account #2 + probability that a randomly selected message comes from account #3 * probability that the message is spam given that the message is from account #3 = 0.6 * 0.01 + 0.3 * 0.03 + 0.1 * 0.05 = 0.02 (2%)

thus the probability is 0.02 (2%)

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Which two points are on the graph of M(a) = - 3/4a-12?
sertanlavr [38]

Answer:

(-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

Step-by-step explanation:

Here, the given expression is : M(a) = -\frac{3}{4} a-12

Here, let M(a)  = b

⇒The equation becomes b = -\frac{3}{4} a-12

Now, check for all the given points for (a,b)

<u>1) FOR (-9,0)</u>

RHS  is  -\frac{3}{4} (-9)-12  =   -5.25 \neq 0

Hence, (-9,0) is NOT on the graph.

<u>2) FOR (-16,0)</u>

Here, LHS = b = 0

andRHS  =   -\frac{3}{4} (-16)-12  = 12-12  = 0

Hence, LHS  =  RHS = 0  So, (-16,0) is  on the graph.

<u>3) FOR (0,12)</u>

Here, LHS = b = 12

RHS  is  -\frac{3}{4} (0)-12  =   -12  \neq 12

Hence, (0,12) is NOT on the graph.

<u>4) FOR (0,-12)</u>

Here, LHS = b = -12

RHS  is  -\frac{3}{4} (0)-12  =   -12

and LHS = RHS = -12

Hence, (0,-12) is  on the graph.

Hence, (-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

6 0
3 years ago
Note: When solving for k, round to four decimals places **
____ [38]
First we find k by using the two values given:
P=Ae^(kt), 8 years between-->t=8
199 = 195•e^(8k)
Log 199 = Log [195•e^(8k)]
Log 199 = Log 195 + 8k
8k = Log 199 - Log 195
k = 0.00882/8 = .0011
Next, we plug the new data in using this k:
14 years between 2002-2016-->t=14
P = Ae^my
P = 199mi.•e^(14•.0011)
P = 199mi.•e^(.0154)
P = 199mi. • 1.0155 = 202,088,000
5 0
2 years ago
To the nearest hundredth, what is the value of m ?
cluponka [151]

Answer:

12.99

Step-by-step explanation:

Cosine is the adjacent side of an angle over the hypotenuse.

cos(30)=m/15

m=cos(30)*15≈12.99

7 0
2 years ago
Hey I really need help in this can someone help me pls and thank you ​
mote1985 [20]

Answer:

12 ¼

Step-by-step explanation:

if you add the 16ths its up to 4 16ths, simplified that is ¼. then you add the 3s, 3 × 4 is 12. add the two, 12 ¼

3 0
2 years ago
6xy — 4 y +6 - 4 x<br> Factorise this expression
otez555 [7]

Answer:

6xy-4y=2x+2x

2x+2x=4xbox

4xbox answer this fraction

4 0
3 years ago
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