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slavikrds [6]
2 years ago
12

Find the derivative of

Mathematics
2 answers:
Anit [1.1K]2 years ago
6 0

Answer:

⇒y'=-\frac{2}{(six-cosx)^{2} }

Step-by-step explanation:

⇒Answer in the attachment.

Gre4nikov [31]2 years ago
3 0

Answer:

<u><em>y' = 1 / sinxcosx</em></u>

Step-by-step explanation:

<u>Given :</u>

y = sinx + cosx / sinx - cosx

<u>Applying quotient rule :</u>

y' = [(sinx - cosx)(cosx - sinx) - (sinx + cosx)(cosx + sinx)] / (sinx -

cosx)²

y' = [sinxcosx - cos²x - sin²x + sinxcosx - (sinxcosx + cos²x + sin²x + sinxcosx)] / (sinx - cosx)²

y' = 2sinxcosx - 2sinxcosx - 2cos²x - 2sin²x / (sinx -cosx)²

y' = -2(sin²x + cos²x) / (sinx - cosx)²

y' = -2 / (sinx - cosx)²

y' = -2 / sin²x - 2sinxcosx + cos²x

y' = -2 / -2sinxcosx

<u><em>y' = 1 / sinxcosx</em></u>  [⇒ Final answer]

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