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Alona [7]
2 years ago
10

Need help!

Mathematics
1 answer:
siniylev [52]2 years ago
8 0

<u>Correct </u><u>Inputs </u><u>:-</u>

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

\underline{\underline{\large\bf{Solution:-}}}\\

\longrightarrow Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

\leadstoMedian is the line segment from a vertex to the midpoint of the opposite side.

<u>Let us Check all options one by one </u>

  • CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

  • BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

  • AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

  • AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

  • AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️
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Make an equation to represent the area of a square whose sides are given by the expression x + y
ki77a [65]

Answer:

x^2 + 2xy + y ^2

Step-by-step explanation:

A = a^2

a = x + y

(x + y) + (x + y)

x^2 + xy + xy + y^2

x^2 + 2xy + y ^2

4 0
3 years ago
Numbers that add to -0.5 and multiply to 1
Oliga [24]
Short Answer
There are two numbers
x1 = -0.25 + 0.9682i   <<<< answer 1
x2 = - 0.25 - 0.9582i   <<<< answer 2 
 
I take it there are two such numbers.
Let one number = x
Let one number = y

x + y = -0.5    
y = - 0.5 - x       (1)
xy = 1               (2)

Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1               Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0          Order these by powers
-x^2 - 0.5x -1 = 0           Multiply though by - 1
x^2 + 0.5x + 1 = 0         Use the quadratic formula to solve this.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 0.5
c = 1


\text{x = }\dfrac{ -0.5 \pm \sqrt{0.5^{2} - 4*1*1 } }{2*1}

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i

x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i

These two are conjugates. They will add  as x1 + x2 = -0.25 - 0.25 = - 0.50.

The complex parts cancel out.  Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.

Check
(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375

Notice
The two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.

The final result is 0.9375 and 0.0625 add up to 1
 
7 0
3 years ago
How do you do this question?
OLEGan [10]

Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

7 0
3 years ago
I kind of understand this question, but I'm not sure how to answer it directly, can someone help please.
nordsb [41]
So here we use the pythagorean theorem which is a2 + b2 = c2 (“a” squared times “b” squared equals “c” squared) the length from calvins house to the intersection is “a” and the length from phoebes house to the intersection is “b” so in order to find out the length of “c” (calvins house to phoebes house) we need to use the pythagorean theorem

a2 275x275=75,625

b2 113x113 = 12,769

so now that we have figured out what a2 and b2 are let’s add them

75,625 + 12,769 = 88,394

now since we only need to find out the length and not the area we need to find the square root of 88,394

the square root of 88,394 is 297.311 (i cut off the decimal after three places)

the direct length from phoebes house to calvins is 297.311 meters
5 0
3 years ago
Please help me due today
Sati [7]

Answer:

1) C. (3, 5)

2) B. Counterclockwise turn 90 degrees about the origin

3) A. C' (0, -2)

Step-by-step explanation:

i got u bro

5 0
3 years ago
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