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Alona [7]
2 years ago
10

Need help!

Mathematics
1 answer:
siniylev [52]2 years ago
8 0

<u>Correct </u><u>Inputs </u><u>:-</u>

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

\underline{\underline{\large\bf{Solution:-}}}\\

\longrightarrow Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

\leadstoMedian is the line segment from a vertex to the midpoint of the opposite side.

<u>Let us Check all options one by one </u>

  • CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

  • BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

  • AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

  • AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

  • AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️
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For fun, if X=180 and Y=20 then what is (Y-X)x(53-33)+3,269= ???? For fun
Masja [62]

Answer:

6,469!

Step-by-step explanation:

180-20=160

53-33=20

160*20=3,200

3,269+3,200=6,469

4 0
3 years ago
if i got 20 on my maths test and 205 in my science and in my english i got 100 what was my total result out of 2000
laiz [17]
The answer is 325, 20 + 205 + 100 = 325
4 0
3 years ago
A machine can seal 179 envelopes in 1 minute. If there are 1,440 minutes in a 24-hour day,how many envelopes can the machine sea
ANTONII [103]
257760 envelopes the machine seal in 1 day<span />
8 0
3 years ago
Lalasa and yasmin are designing a triangular banner to hang in the school gymnasiums. They first draw the design on paper. The t
jasenka [17]
<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
</span><span>
If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>

5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>

regarding feet: 

The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
</span>

3 0
3 years ago
Solve the equation. \dfrac18 + c = \dfrac45 8 1 ​ +c= 5 4 ​ start fraction, 1, divided by, 8, end fraction, plus, c, equals, sta
aivan3 [116]

Answer:

c=\dfrac{27}{40}\\

Step-by-step explanation:

We are required to solve for c in the equation: \dfrac{1}{8}+c= \dfrac{4}{5}

Step 1: Collect like terms

\dfrac{1}{8}+c= \dfrac{4}{5}\\c= \dfrac{4}{5}-\dfrac{1}{8}

Step 2: Find the Lowest Common Multiple of the denominators

LCM of 8 and 5 is 40

Step 3: Multiply all through by 40

40c= \dfrac{4}{5}*40-\dfrac{1}{8}*40

Step 4: Simplify

40c=32-5

40c=27

Step 5: Divide both sides by 40 and simplify if possible.

c=\dfrac{27}{40}\\

4 0
3 years ago
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