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Alona [7]
2 years ago
10

Need help!

Mathematics
1 answer:
siniylev [52]2 years ago
8 0

<u>Correct </u><u>Inputs </u><u>:-</u>

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

\underline{\underline{\large\bf{Solution:-}}}\\

\longrightarrow Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

\leadstoMedian is the line segment from a vertex to the midpoint of the opposite side.

<u>Let us Check all options one by one </u>

  • CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

  • BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

  • AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

  • AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

  • AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️
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