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3 years ago

13

How many cubes with an edge length of 1/2 are needed to build a cube with an edge length of 1 inch

1 answer:

BARSIC [14]3 years ago

7 0

Answer:

8 cubes

Step-by-step explanation:

1^3=1

(1/2)^3=1/8

1/(1/8)=1*8=8

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Help with the following problem please

Effectus [21]

Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle = $\pi R^2=\pi7^2=49\pi$
Area of large shaded circle = $\pi x^2=\pi5^2=25\pi$
Area of 4 small shaded circles = $4\pi r^2=4\pi1^2=4\pi$
Total area of shaded circles = $25\pi+4\pi=29\pi$

Shaded area as a fraction of that of the outer circle
$=\frac{29\pi}{49\pi}=29/49$

3 0

3 years ago

One step equations<br> 6r=42

zvonat [6]

R=7

I hope that help you! :)

3 0

3 years ago

Read 2 more answers

What integer increased by - 12 is 28?

guajiro [1.7K]

Answer:

40

Step-by-step explanation:

Let n represent the integer. Then the increase can be written as ...

n + (-12) = 28

We can add 12 to both sides of this equation:

n + (-12) + (+12) = 28 +12

n + 0 = 40 . . . . . . -12 and 12 total to zero; 28 and 12 total to 40.

n = 40

The integer is 40.

4 0

3 years ago

There are 135 people and three door prizes. how many ways can door prizes of $7,500, $750 and $75 be distributed?

igomit [66]

Answer: 2405970 ways

Step-by-step explanation:

When the order of selecting r individuals out of n individual , we use permutations.

The number of permutations of r things taking out of n things is given by :-

$^nP_r=\dfrac{n!}{(n-r)!}$

Given : There are 135 people and three door prizes .

i.e. n= 135 , r= 3

Then, the total number of ways = $^{135}P_3=\dfrac{135!}{(135-3)!}$

$=\dfrac{135\times134\times133\times132!}{132!}\\\\=135\times134\times133\\\\=2405970$

Hence, there are 2405970 ways to distribute door prizes of $7,500, $750 and $75 .

6 0

4 years ago

Find two positive consecutive integers such that the square of the first added to three times the second is 24

Naddika [18.5K]

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

$x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6$

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.

7 0

3 years ago