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Stels [109]
2 years ago
12

The value of a stock in 1940 is $1.25. Its value grows by 7% each year after 1940.

Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

toStep-by-step explanation:

1.25 each year plus 7% for each year

V(t) = t(m) + (c)

m is the gradient

c is the y-intercept

first m

m is what it changes by each year

it is 7% as it changes by 7% each year

we need 7% as a decimal though so

what is 7% as a decimal

write in comments if you don't know tell me

then i will do c

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a shirt was bought for ₩ 528 after getting a discount of 12 % on its market price find the market price of the shirt
BlackZzzverrR [31]

528 - (528 \times .12) = answer
4 0
3 years ago
Evaluate the expression if a=2,b=-3,C=-1, and D=4<br><br><br> -2(b^2-5c)
Alenkasestr [34]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • Equivalent value = -28

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \: - 2( {b}^{2}  - 5c)

( put the values )

\qquad❖ \:  \sf \: - 2 \{( - 3) {}^{2}  - 5( - 1) \}

\qquad❖ \:  \sf \: - 2(9 -  (- 5))

\qquad❖ \:  \sf \: - 2(9 + 5)

\qquad❖ \:  \sf \: - 2 \times 14

\qquad❖ \:  \sf \: - 28

\qquad \large \sf {Conclusion}  :

  • -2(b² - 5c) = -28

7 0
1 year ago
Maria calls her mother 5 times every week. Let w represent the number of weeks and c represent the total number of times Maria c
galina1969 [7]

Answer:

Equation: 5w = c

Step-by-step explanation:

{ \tt{w \:  \alpha \: c}} \\ { \tt{w = kc}}

k is a constant of proprtionality

{ \tt{1 = (k \times 5)}} \\ { \tt{k =  \frac{1}{5} }}

» Therefore, equation becomes:

{ \tt{w =  \frac{1}{5}c }} \\  \\ { \boxed{ \tt{5w = c}}}

8 0
2 years ago
The cost of attendance at State College is $19,500 for the first year. Devise a periodic savings plan that will allow you to mak
ValentinkaMS [17]
We are told to use simple interest rate. Formula for this is:
A=P*(1+r*t)

Where:
A= total accumulated amount (principal + interest)
P= principal
r= yearly percentage rate
t= number of years

We need to save $19500 for the first year at a college. This is the amount we will have at the account after five years. In our case this is A.
Principal is the amount we need to put into savings to get the total amount needed. In our case this is P.
Yearly percentage rate is the percentage by which our savings increase at the end of a year. In our case this is r.
t is number of years that we are holding our money on the bank account.

To solve this problem we will assume that we are putting same amount each month on the bank account.

We are given:
A=$19500
P=?
r=1.5%
t=5 years

First step is to transform r into decimal number:
r= \frac{1.5}{100} =0.015

Now we get back to our formula and we solve it for P:
A=P*(1+r*t) \\ P= \frac{A}{1+r*t}
We insert numbers and we get our principal:
P= \frac{19500}{1+0.015*5}  \\ P=18139.53

We need to put $18139.53 into savings to get required amount after 5 years or 5*12=60months. Assuming that we put same amount each month into savings we need to put
18139.53 / 60 = 302.33

This is our solution for this problem. This is closest to the amount we would need to put in real life. In real life we would earn interest onto interest and our monthly amount would be smaller.
3 0
3 years ago
Which of the following equations has no solution?
Ronch [10]

Answer:

B and D

Step-by-step explanation:

Equations with the same x- term on both sides will have no solution

A

4x - 13 = 5(x + 4) = 5x + 20

4x ≠ 5x

This equation has a solution

B

5(3 + 2x) = 10x + 4

15 + 10x = 10x + 4

10x on both sides ⇒ no solution

C

2(3 - 5x) = 8(x + 1)

6 - 10x = 8x + 8

- 10x ≠ 8x

This equation has a solution

D

9x - 6 = 3(3x - 2) = 9x - 6

9x on both sides ⇒ no solution

8 0
2 years ago
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