1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sedaia [141]
3 years ago
15

The density of blood is 2kg/m.convert to g/cm

Physics
1 answer:
sertanlavr [38]3 years ago
6 0

Explanation:

if we convert it into g/cm it'll be

2000 grams

You might be interested in
Un autobús viaja en una carretera a una velocidad de 70 km/h y acelera durante 30 segundos hasta llegar a su límite de velocidad
nalin [4]

Answer:

a = 30 km / h²

Explanation:

Dado que

Velocidad inicial, u = 70 km / h

Velocidad final, v = 95 km / h

Tiempo, t = 30 s = 0.1 h

Lo sabemos

v = u + a t

a = aceleración

Ahora poniendo los valores en la ecuación anterior

95 = 70 + a \ times 0.1


a = \ dfrac {95-70} {0.1} = 30 \ km / h ^ 2


Por lo tanto, la aceleración será

a = 30 km / h²

4 0
4 years ago
Alkali Metals- 1 valence electron __________________&__________________.
Paraphin [41]
Hi , I think that the elements that have one valence electron and that are in the alkali metals  are the answers .
1.lithium
2.sodium
3.potassium
4.rubidium
5.cesium
6.francium
8 0
4 years ago
A cannonball fired with an initial speed of 40 m/s and a launch angle of 30 degrees from a cliff that is 25m tall.
KATRIN_1 [288]
We know that the ball traveled with an initial velocity of 40m/s at a 30° angle above the horizontal. The image below shows how much of this velocity was upward velocity and how much was horizontal velocity. Upward velocity was 20 m/s and horizontal velocity was √(40) m/s, or 2√(10) m/s. We get these numbers from the ratios of the 30-60-90 triangle. 

a) What is the flight time of the cannonball?
The flight time of the cannonball can be found by finding the time at which the upward velocity equals zero (the top of the ball's trajectory) and then finding how long it took to hit the ground after that point.

To find where upward velocity equals zero:
V = Vi - a(t) ,  where V equals vertical velocity, Vi equals initial vertical velocity, and a equals acceleration due to gravity (-9.8 m/s²)
V = 20 - 9.8(t)          Set V equal to zero, because we want to find the moment when the ball reached the peak of its travel path
0 = 20 -9.8t         Add 20 to both sides, then divide by 9.8
t = 2.041
This is the point where the ball was at the top of its trajectory.

At this point, How high was the ball?
d = Vi x t + (1/2) (a) (t²) , where d is distance traveled
d = 20(2.041) + (1/2) (-9.8) (2.041²)
d = 20.388
Remember that the ball was launched from 25 m above the ground, so add 25 to the height that the ball traveled from this point:
25 + 20.388 = 45.388
This was the height the ball reached before it started to come down. Plug this into the distance formula to see how long it took to hit the ground. Remember that this is similar to the ball being dropped from rest from this height, since vertical velocity was zero.
45.388 = (0)(t) - (1/2) (-9.8) (t²)    Multiply both sides by (-2/-9.8)
9.26 = t²
t = 3.043
We know that it took 2.041 seconds to reach the peak height, and 3.043 seconds to come down. 
Total flight time = 2.041 + 3.043 = 5.084 seconds

Remember that, neglecting air resistance, the ball will maintain the same horizontal velocity the entire time. This means the horizontal velocity was 10√2 during the entire flight time.
distance = velocity * time = 5.084 * 10√2 = 32.154

5 0
4 years ago
A cantilever beam with a width b=100 mm and depth h=150 mm has a length L=2 m and is subjected to a point load P =500 N at B. Ca
DerKrebs [107]

Answer:

Explanation:

Given that:

width b=100mm

depth h=150 mm

length L=2 m =200mm

point load P =500 N

Calculate moment of inertia

I=\frac{bh^3}{12} \\\\=\frac{100 \times 150^3}{12} \\\\=28125000\ m m^4

Point C is subjected to bending moment

Calculate the bending moment of point C

M = P x 1.5

= 500 x 1.5

= 750 N.m

M = 750 × 10³ N.mm

Calculate bending stress at point C

\sigma=\frac{M.y}{I} \\\\=\frac{(750\times10^3)(25)}{28125000} \\\\=0.0667 \ MPa\\\\ \sigma =666.67\ kPa

Calculate the first moment of area below point C

Q=A \bar y\\\\=(50 \times 100)(25 +\frac{50}{2} )\\\\Q=250000\ mm

Now calculate shear stress at point C

=\frac{FQ}{It}

=\frac{500*250000}{28125000*100} \\\\=0.0444\ MPa\\\\=44.4\ KPa

Calculate the principal stress at point C

\sigma_{1,2}=\frac{\sigma_x+\sigma_y}{2} \pm\sqrt{(\frac{\sigma_x-\sigma_y}{2} ) + (\tau)^2} \\\\=\frac{666.67+0}{2} \pm\sqrt{(\frac{666.67-0}{2} )^2 \pm(44.44)^2} \ [ \sigma_y=0]\\\\=333.33\pm336.28\\\\ \sigma_1=333.33+336.28\\=669.61KPa\\\\\sigma_2=333.33-336.28\\=-2.95KPa

Calculate the maximum shear stress at piont C

\tau=\frac{\sigma_1-\sigma_2}{2}\\\\=\frac{669.61-(-2.95)}{2}  \\\\=336.28KPa

6 0
3 years ago
Two hockey players are about to collide on the ice, One player has a mass of
Furkat [3]

Answer:

19 kg x m/s East

Just did it!

3 0
3 years ago
Other questions:
  • A 1200 kg frictionless roller coaster starts from rest at a height of 19 m. What is its kinetic energy when it goes over hill th
    11·1 answer
  • O need help with this please
    10·1 answer
  • A 2.3 kg block of copper is heated at atmospheric pressure such that its temperature increases from 6 oC to 90 oC. How much heat
    10·1 answer
  • If the wavelength of orange light is 6 · 10-7 m, calculate its frequency. f = _______ Hz
    14·1 answer
  • {WILL GIVE (Brain lies t) TO FULL ANSWERS}
    7·2 answers
  • A balloon contains 30.0 l of helium gas at 103 kpa.
    15·1 answer
  • Calculate the change in momentum of a 45 kg runner who starts out at 1 m/s and speeds up to 3 m/s. Which anser choice is correct
    13·1 answer
  • A track star runs the first 500 meters of a race in only 75 seconds. What is the track
    10·2 answers
  • A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m.
    12·1 answer
  • Calculate by how much a spring with spring constant 1.2N/m has been squashed when it has stored 76J,
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!