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Serjik [45]
3 years ago
9

A man pushes a lawn mower with a force of 200 N across 50 meters of his lawn. How much work did the man perform?

Physics
1 answer:
Aleks [24]3 years ago
8 0
Work = force x distance. So the answer would be 200x50=10000 joules
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MATCH THESE ^-^ Match Newton's law with the correct statement.
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what evidence can you cite that the interstellar medium contains both gas and dust? (select all that apply.)
Basile [38]

(a) The gas of interstellar medium can be detected from the radiations of photons of  wavelength 21 cm.

(b) The gas of interstellar medium can be detected from the absorption lines present in the light from distant stars, which must be caused by a medium of density and temperature other than that of the stars emitting the lights.

<h3>What is interstellar medium?</h3>

Interstellar medium is the matter and radiation that exist in the space between the star systems in a galaxy.

<h3>Evidence that interstellar medium contains both gas and dust</h3>
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  • The gas of interstellar medium can be detected from the absorption lines present in the light from distant stars, which must be caused by a medium of density and temperature other than that of the stars emitting the lights.

Learn more about  interstellar medium here: brainly.com/question/4173326

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4 0
2 years ago
Our milky way galaxy is 100000 lyly in diameter. a spaceship crossing the galaxy measures the galaxy's diameter to be a mere 1.
Sidana [21]

The speed of the spaceship relative to the galaxy is 0.99999995c.

A light-year measures distance rather than time (as the name might imply). A light-year is a distance a light beam travels in one year on Earth, which is roughly 6 trillion miles (9.7 trillion kilometers). One light-year equals 5,878,625,370,000 miles. Light moves at a speed of 670,616,629 mph (1,079,252,849 km/h) in a vacuum.We multiply this speed by the number of hours in a year to calculate the distance of a light-year (8,766).

The Milky way galaxy is 100,000 light years in diameter.

The galaxy's diameter is a mere 1. 0 ly.

We know that ;

L = L_0 \sqrt{1-\frac{v^2}{c^2} }

L = 1 light year

L₀ = 100,000 light year

1 = 100,000 \sqrt{1-\frac{v^2}{c^2} }

1 = 100,000 \sqrt{1-\frac{v^2}{(3*10^8)^2} }

\frac{1}{100,000}  = \sqrt{1-\frac{v^2}{c^2} }

v = 0.999999995 c

Therefore, the speed of the spaceship relative to the galaxy is 0.99999995c.

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brainly.com/question/17423632

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5 0
1 year ago
Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an i
romanna [79]

Answer:

v_f=0.825m/s

Explanation:

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p_i=p_1+p_2=m_1v_1+m_2v_2

where these are the masses are initial velocities of both players.

After the collision we have:

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since they clong together, acting as one body.

This means we have:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Or:

v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Which for our values is:

v_f=\frac{(98.5kg)(6.05m/s)+(119kg)(-3.5m/s)}{(98.5kg)+(119kg)}=0.825m/s

7 0
3 years ago
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