Answer:
And if we count the number of zeros before the number 7, we can rewrite the number like this:
We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:
And if we count the number of zeros before the number 7, we can rewrite the number like this:
We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
C
substitute a = - 1 into the expression
- (- 1) - 12(- 1)² = 1 - (12 × 1 ) = 1 - 12 = - 11 → C
Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³
The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³
Now, the number of boxes that can fit in the cargo hold of the truck will be,
Number of boxes = (Volume of truck container)/(Volume of box)
= 843.75/15.625
= 54
Hence, the number of boxes that can fit in the cargo hold of the truck is 54.
Learn more about Volume:
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Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
I started with c, but you could’ve started with any box.
So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.
Then I went to a. All of a’s numbers were divisible by 7.
Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!
Then d. Two are divisible by 7, so your rules is divisible by 2.
I hope this helps!
