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serious [3.7K]
2 years ago
6

CaCl2 (s) + 2 H2O → Ca(OH)2 (aq) + 2 HCl (g) When Addie added CaCl2 to the water in her flask, she noted that the flask heated u

p. What conclusion can be drawn about the bond energy of products and reactants? A) More energy was absorbed in the formation of chemical bonds than released in the breaking of chemical bonds. B) Less energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds. C) More energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds. D) Less energy was absorbed in the formation of chemical bonds than released in the breaking of chemical bonds.
Chemistry
1 answer:
zloy xaker [14]2 years ago
3 0

Answer: the answer is b

Explanation: the formation of bonds releases energy and the breaking of bonds always involves an absorption of energy

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Rutherford, geiger, and marsden’s experiment demonstrated that the volume of the nucleus is roughly what fraction of the volume
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2 years ago
nswer the following questions relating to HCl, CH3Cl, and CH3Br.HCl(g), can be prepared by the reaction of concentrated H2SO4(ag
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Answer:

It is an example of double displacement reaction.

4.8 g of NaCl is needed to react.

Explanation:

Balanced reaction: H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)

Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.

In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.

As H_{2}SO_{4}(aq.) remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.

Molar mass of HCl = 36.46 g/mol

So, 3.0 g of HCl = \frac{3.0}{36.46} mol of HCl = 0.082 mol of HCl

According to balanced equation-

2 moles of HCl are produced from 2 moles of NaCl

So, 0.082 moles of HCl are produced from 0.082 moles of NaCl

Molar mass of NaCl = 58.44 g/mol

So, mass of 0.082 moles of NaCl = (0.082\times 58.44) g = 4.8 g

Hence 4.8 g of NaCl is needed to react.

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