It is given that the surface area of sphere is 4 π r² and its volume is (4/3 π r³)
With a diameter of 1.2 mm you have a radius of 0.6 mm so the surface area about 4.5 mm² and the volume is about 0.9 mm³
The total surface energy of the original droplet is (4.5 x 10⁻⁶ m x 72) = 3.24 x 10⁻⁴mJ
The five smaller droplets need to have the same volume as the original so:
5 V = 0.9 mm³ so the volume of smaller sphere will equal 0.18 mm³
Since this smaller volume still have volume (4/3 π r³) so r = 0.35 mm
Each of the smaller droplets has a surface are = 1.54 mm²
The surface energy of the 5 smaller droplet is then (5 x 1.54 x 10⁻⁶ m x 72) = 5.54 x 10⁻⁴ mJ
From this radius the surface energy of all smaller droplets is 5.54 x 10⁻⁴ and the difference in energy is (5.54 x 10⁻⁴) - (3.24 x 10⁻⁴) = 2.3 x 10⁻⁴ mJ
Therefore we need about 2.3 x 10⁻⁴ mJ of energy to change a spherical droplet of water of diameter 1.2 mm into 5 identical smaller droplets
Answer:
A is a physical change, no atoms are being lost its still in it original form
B is a chemical change, it is losing atoms and changing into a new substance
Explanation:
The precipitate of reaction that occurs when silver nitrate solution is mixed with sodium chloride solution is of silver chloride (AgCI).
The chemical equation for this precipitation reaction is as following:
AgNO3(aq) + NaCl(aq) --> AgCl(s) [precipitate]+NaNO3(aq)
- Silver Chloride is a chemical compound which is poorly soluble in water because the chemical bond between Ag+ and Cl is very strong as the two ions are nearly the same size and have similar electronic densities.
- If the chemical bond is strong, it is difficult for water molecules to break this bond to surround the individual ions, thus solubility will decrease.
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