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jeka94
4 years ago
13

Oxygen gas is collected over water. The total pressure (the O2 pressure the water vapor pressure) is 736 torr. The temperature o

f the water is such that the water vapor pressure is 46 torr. What is the partial pressure of the oxygen gas in torr
Chemistry
1 answer:
tigry1 [53]4 years ago
3 0

Answer:

The value of the partial pressure of the oxygen  P_{O_{2} } =  690 torr

Explanation:

Total pressure of the mixture of gases = 736 torr

The partial pressure of water vapor = 46 torr

From the law of pressure we know that

Total pressure = The partial pressure of water vapor + The partial pressure of oxygen O_{2}

Put the values of pressures in above equation we get,

⇒ 736 = 46 + P_{O_{2} }

⇒ P_{O_{2} } = 736 - 46

⇒ P_{O_{2} } =  690 torr

This is the value of the partial pressure of the oxygen.

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Pyrite has a metallic luster. which sample is most likely pyrite?
kupik [55]

Answer:

C

Explanation:

others are boring or gems

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3 years ago
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The accepted value for the density of iron is 7.9 g/mL. Four student groups examine the density of iron in the lab. Which of the
nalin [4]

For 5.43 g/mL and 5.44 g/mL =  0.01 the least diff and most precise.

First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.

For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01

For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07

For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01

For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03

As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.

To know more about precision visit :

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3 0
2 years ago
Water beads up on waxy surfaces because of a degree of adhesion with the surface. True or False
Soloha48 [4]
False.  Water is basically better at sticking to itself than it is in sticking to the wax.
8 0
4 years ago
g A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is __________ compared to a 300 mOsM sol
ICE Princess25 [194]

Answer:

A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

Explanation:

The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

When they are dissolved in water, they dissociate into particles as follows:

NaCl → Na⁺ + Cl⁻  (2 particles per compound)

CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)

urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm

Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl  and CaCl₂) is calculated as:

Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm

Therefore, we have:

Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution

Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic

4 0
3 years ago
A gas at 76 K is under a pressure of 78.4 kPa. If the temperature changes to 105 what will be the new
8_murik_8 [283]

Answer:

108.3kPa

Explanation:

Given parameters:

Initial temperature  = 76k

Initial pressure  = 78.4kPa

Final temperature  = 105k

Unknown:

Final or new pressure  = ?

Solution:

To solve this problem, we apply the combined gas law:

           \frac{P_{1} }{T_{1} }     =    \frac{P_{2} }{T_{2} }

T1 = 76k

P1  = 78.4kPa

T2  = 105k

     \frac{78.4}{76}   = \frac{P_{2} }{105}  

     P2 = 108.3atm

7 0
3 years ago
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