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2 years ago

Salt formed by the partial neutralization of an acid by a base are

Chemistry

1 answer:

Makovka662 [10]2 years ago

4 0

Answer:

D. Acidic salt

Explanation:

Acidic salts:

Salts formed by incomplete neutralisation of poly-basic acids are called acidic salts. Such salts still contain one or more replaceable hydrogen atoms. These salts when neutralised by bases form normal salts.

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Describe how sediments are produced by weathering and erosion

TEA [102]

Weathering is the physical or chemical process where rocks are broken down to form sediments.
• Physical weathering does not change the rock’s composition.
• Chemical weathering does change the rock’s composition
• Erosion is the process where forces such as water, wind, ice, or gravity transport sediments to some remote location

5 0

3 years ago

Read 2 more answers

Place the following in order of increasing X-Se-X bond angle, where X represents the outer atoms in each molecule. SeO2 SeCl6 Se

GalinKa [24]

Answer:

SeCl₆ < SeF₂ < SeO₂

Explanation:

(A) SeO₂

The central atom has 2 bond pairs and 1 lone pair. The molecule is bent shaped which has an angle of 120°.

(B) SeCl₆

The central atom has 6 bond pairs and 0 lone pair. The geometry is octahedral in which the equatorial bonds has an angle of 90° and axial bond has an angle of 90°.

The central atom has 2 bond pairs and 2 lone pairs. The geometry is bent shape which has an angle of approximately 105.5°.

The order is:

SeCl₆ < SeF₂ < SeO₂

5 0

3 years ago

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the

Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}$

$P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}$

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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4 0

1 year ago

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.

Answer: The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

Explanation:

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

For copper metal:

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of copper metal

So, 6 moles of silver nitrate will react with = $\frac{1}{2}\times 6=3mol$ of copper metal

Moles of copper reacted = 3 moles

For copper(II) nitrate:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = $\frac{1}{2}\times 6=3mol$ of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

For silver metal:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = $\frac{2}{2}\times 6=6mol$ of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

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3 years ago

Meiosis occurs in embryo cells plant cells reproductive cells animal cell

Law Incorporation [45]

Answer:

Meiosis is a type of cell division - like mitosis, but it results in four haploid cells with one-half the number of chromosomes as the original diploid cell. Meiosis occurs in plants only during sexual reproduction in specialized cells to produce a haploid egg cell.

4 0

2 years ago