Question

The effusion rate of hcl is 43. 2 cm/min in a certain effusion apparatus. What is the rate of effusion of ammonia in the same apparatus?.

Answer 1

The rate of effusion of ammonia (NH₃) in the same apparatus is 63.3 cm/min

Graham's law of diffusion

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

How to determine the rate of ammonia (NH₃)

• Rate of HCl (R₁) = 43.2 cm/min
• Molar mass of HCl (M₁) = 1 + 35.5 = 36.5 g/mol
• Molar mass of NH₃ (M₂) = 14 + (3×1) = 17 g/mol

• Rate of NH₃ (R₂) =?

R₁/R₂ = √(M₂/M₁)

43.2 / R₂ = √(17 / 36.5)

Cross multiply

43.2 = R₂ × √(17 / 36.5)

Divide both side by √(17 / 36.5)

R₂ = 43.2 / √(17 / 36.5)

R₂ = 63.3 cm/min

Thus, the rate of effusion of ammonia is 63.3 cm/min

Learn more about Graham's law of diffusion:

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