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devlian [24]
3 years ago
15

Blast furnaces extract pure iron from the iron(III) oxide in iron ore in a two step sequence. In the first step, carbon and oxyg

en react to form carbon monoxide: (s)(g)(g) In the second step, iron(III) oxide and carbon monoxide react to form iron and carbon dioxide: (s)(g)(s)(g) Write the net chemical equation for the production of iron from carbon, oxygen and iron(III) oxide. Be sure your equation is balanced.
Chemistry
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

6 C(s) +  3 O₂(g) + 2 Fe₂O₃(s) →  4 Fe(s) + 6 CO₂(g)

Explanation:

Iron can be formed in two steps.

Step 1: 2 C(s) + O₂(g) → 2 CO(g)

Step 2: Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g)

In order to get the net chemical equation, we will multiply the first step by 3, the second step by 2, and then add them.

6 C(s) +  3 O₂(g) → 6 CO(g)

+

2 Fe₂O₃(s) + 6 CO(g) → 4 Fe(s) + 6 CO₂(g)

--------------------------------------------------------------------------------------------------

6 C(s) +  3 O₂(g) + 2 Fe₂O₃(s) + 6 CO(g) → 6 CO(g) + 4 Fe(s) + 6 CO₂(g)

6 C(s) +  3 O₂(g) + 2 Fe₂O₃(s) →  4 Fe(s) + 6 CO₂(g)

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The molecular formula of dimethyl sulfoxide is (CH_{3})_{2}SO. Molar mass of dimethyl sulfoxide is 78.13 g/mol. Calculate number of moles as follows:

n=\frac{m}{M}=\frac{7.14\times 10^{3} g}{78.13 g/mol}=91.38 mol

From the molecular formula, 1 mole of dimethyl sulfoxide contains 2 moles of Carbon, 6 moles of Hydrogen, 1 mole of Sulfur and 1 mole of oxygen.

Thus, 91.38 moles of dimethyl sulfoxide will have:

Carbon :

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Hydrogen:

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Sulfur:

n_{S}=1\times 91.38 moles=91.38 moles

Oxygen:

n_{O}=1\times 91.38 moles=91.38 moles

Since, 1 mole of an element equals to 6.023\times 10^{23} atoms thus, number of atoms can be calculated as:

Carbon:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

182.77 moles\rightarrow 182.77\times 6.023\times 10^{23} atoms=1.10\times 10^{26} atoms

Hydrogen:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

548.28 moles\rightarrow 548.28\times 6.023\times 10^{23} atoms=3.30\times 10^{26} atoms

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1 mole\rightarrow 6.023\times 10^{23} atoms

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91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms

Oxygen:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms

Therefore, number of C, S, H and O atoms are 1.10\times 10^{26}, 5.50\times 10^{25}, 3.30\times 10^{26} and 5.50\times 10^{25} atoms respectively.

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Answer:

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[CH3COOH] [CH3COO-

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initial 0.100 0.100 ≈0

-x x x

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Ka = [CH3COO-

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Explanation:

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