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Natasha_Volkova [10]
2 years ago
13

How many moles of carbon dioxide are produced from the combustion of 110 g of ch4.

Chemistry
1 answer:
viva [34]2 years ago
8 0

Answer:

answer: 6.875 moles

Explanation:

nCH4 = nCO2 = 110/(12 + 4) = 6.875

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The melting point of a substance is the temperature at which it change state from solid to liquid is called crystallization point.

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3 years ago
In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?
sertanlavr [38]

Answer:

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8 0
3 years ago
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula
Dafna11 [192]

\\ \sf\longmapsto FeP

\\ \sf\longmapsto Fe_2S_3

\\ \sf\longmapsto FeCl_2

\\ \sf\longmapsto MgCl_2

\\ \sf\longmapsto MgO

\\ \sf\longmapsto Mg_3N_2

\\ \sf\longmapsto Na_3P

\\ \sf\longmapsto Na_2S

\\ \sf\longmapsto CoO

\\ \sf\longmapsto Co_2S_3

\\ \sf\longmapsto AlCl_3

\\ \sf\longmapsto CsBr

\\ \sf\longmapsto Ti_2O_4

\\ \sf\longmapsto Ag_2S

4 0
2 years ago
How many moles of NH3 can be produced from 30.0 mol of H2 and excess N2?
VMariaS [17]
20 mol of NH, can be produce from 30 mol o H2
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3 years ago
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