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2 years ago

Is -2 degrees Fahrenheit warmer or is -17 degrees fahrenheit?

Chemistry

1 answer:

guapka [62]2 years ago

8 0

-2 degrees would be warmer than -17 because the higher the number gets in the negatives the lower the temperature

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Is methylene chloride more or less dense than water?

horsena [70]

Methylene chloride is less dense than water

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3 years ago

A chef makes a marinade by mixing red pepper flakes, dried onion flakes, and a ground ginger with soy sauce. He sets the marinad

Alisiya [41]

Answer:

Suspension

Explanation:

This mixture is a simple suspension.

A suspension is a mixture of small insoluble particles of a solid in a liquid or gas. Here, it is insoluble particles in liquid.

Suspensions are settle on standing this is why they have to be mixed again.
The particles do not pass through ordinary filter paper.
They are usually cloudy and have an opaque color.
The marinade is simply a suspension.
It is not a solution because they do not settle on standing.
Also, colloids do not settle on standing.

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3 years ago

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List some general characteristic of producers and list and a few examples

kotykmax [81]

Answer:

pooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooop

Explanation: fart

8 0

3 years ago

Drag the appropriate elements to their respective bins

kakasveta [241]

Well you have to do it because nobody on here has the answer choices but you

4 0

3 years ago

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How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?

meriva

Answer:

$\large \boxed{\text{77.4 mL}}$

Explanation:

Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

V/mL: 249

c/mol·L⁻¹: 0.0443 0.285

1. Calculate the moles of Ba(OH)₂

$\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}$

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

$\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}$

3. Calculate the volume of HCl

$V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}$

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3 years ago