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podryga [215]
3 years ago
10

How many moles are in 175.9 grams of Pb3(PO4)2?

Chemistry
1 answer:
snow_lady [41]3 years ago
8 0

Answer:

0.21674767727138733

Explanation:

Again I don't want to give an explanation right now because I can't exactly do that more than once. it hurts my child brain. And the fact that I just woke up.

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Need answer ASAP!!!!
Keith_Richards [23]

Answer:

I am sure it is D or C. have a nice day

6 0
2 years ago
A sample of oxygen occupied 626 mL when the pressure increased to 874.27 mm Hg. At constant temperature, what volume did the gas
Usimov [2.4K]

Answer:

709 (With sig figs)

Explanation:

Pressure(1) * volume(1) = Pressure(2) * volume(2)

771.75 mm Hg * unknown = 874.27 mm Hg * 626 mL

771.75 mm Hg * unknown = 547,293.02 mm Hg*mL

   Divide both sides by 771.75 mm Hg

Unknown = 709 (With sig figs)....709.158432 (without sig figs)

4 0
2 years ago
5.00 g of carbon were adiabatically burned to CO2 in a 2.00 kg copper calorimeter which contained 2.50 kg of water. The temperat
lorasvet [3.4K]

Answer:

A. -163.96kJ

B. -158.34kJ

Explanation:

Heat of combustion is the heat released when an element with oxygen at stp.

Reaction for the combustion of carbon:

C(s) + O2(g) --> CO2(g)

Enthalpy heat of combustion, C (using Hess law) = -393.5 kJ/mol

m = 5g

Molecular weight = 12 g/mol

No of moles = mass/molecular weight

= 5/12

= 0.417mol

DH = -393.5 * 0.417

= -163.96 kJ

B. Heat absorbed by the calorimeter = heat evolve by combustion

= mCH2ODT + mCcDT

Where CH2O is the specific heat capacity of the water in the calorimeter

Cc is the specific heat capacity of copper calorimeter

= (2500*4.184*14.1) + (2000*0.385*14.1)

= -158343J

= -158.34kJ

3 0
3 years ago
Different kinds of light are all around us everyday, but we are invisible to it. Explain the type of light that is visible to hu
belka [17]

Answer:

The human eye can only see white visible light and it contains all the colors of the rainbow, from red to violet.

Explanation:

But visable light comes in many "colors" such as radio, infrared, ultraviolet, X-ray, and gamma-ray that are invisible to the naked eye.The reason that the human eye can see the spectrum is because those specific wavelengths stimulate the retina in the human eye.

8 0
3 years ago
How many atoms are in 73.9g of potassium oxide
denis-greek [22]

Answer: 4.69(10)^{23} atoms

Explanation:

Firstly, we have to find the Molecular mass of potassium oxide (K_{2}0):

K atomic mass: 39 u

O atomic mass: 16 u

K_{2}O molecular mass: 39(2) g/mol+16g/mol=94 g/mol

This means that in 1 mole of K_{2}O there are 94 g and we need to find how many moles there are in 73.9 g K_{2}O:

1 mole of K_{2}O-----94 g of K_{2}O

X-----73.9 g of K_{2}O

X=\frac{(73.9 g)(1 mole)}{94 g}

X=0.78 mole This is the quantity of moles in 73.9 g of potassium oxide

Now we can calculate the number of atoms in 73.9 g of potassium oxide by the following relation:

N_{atoms}=(X)(N_{A})

Where:

N_{atoms} is the number of atoms in 73.9g of potassium oxide

N_{A}=6.0221(10)^{23}/mol is the Avogadro's number, which is determined by the number of particles (or atoms) in a mole.

Then:

N_{atoms}=(0.78 mole)(6.0221(10)^{23}/mol)

N_{atoms}=4.69(10)^{23} atoms This is the quantity of atoms in 73.9g of potassium oxide

6 0
3 years ago
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