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podryga [215]
3 years ago
10

How many moles are in 175.9 grams of Pb3(PO4)2?

Chemistry
1 answer:
snow_lady [41]3 years ago
8 0

Answer:

0.21674767727138733

Explanation:

Again I don't want to give an explanation right now because I can't exactly do that more than once. it hurts my child brain. And the fact that I just woke up.

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Perform the following
Sati [7]

Answer:

35.05152

Explanation:

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A sample of chromium oxide is 76.5hromium by weight. what is the simplest formula of the oxide?
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CrO and Cr₂O₃ make up the simplest chromium oxide formula.

What name does Cr₂O₃ use?

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6 0
1 year ago
Elements consist of tiny particles called
Nutka1998 [239]
The answer is atoms good luck
4 0
3 years ago
Use the iupac nomenclature rules to give the name for this compound - n2o3.
wel
  By  use   IUPAC  nomenclature   rule  compound  N2O3  is  named  as  

Dinitrogen  trioxide  (  answer  d)

Nitrogen (N2) is  named  before  oxygen(O3)  since    they  are  arranged  alphabetically.  In   addition  the  prefix  Di  is   used   infront  of  nitrogen  since    they  are  two  nitrogen  atoms   while  prefix  tri  is   used  infront  of  oxide  since  they  are 3   oxygen   atoms
8 0
2 years ago
Read 2 more answers
The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.376 g sample of e
hoa [83]

Answer:

The answer to your question is: C₄H₁₀O

Explanation:

Data

          CxHyOz

mass sample : 1.376 g

mass CO₂ = 3.268 g

mass H₂O = 1.672 g

Process

Reaction

                      CxHyOz  + O₂ ⇒   CO₂  +  H₂O

1.- Calculate the moles and mass of carbon

Molecular mass CO₂ = 44g

                      44 g of CO₂ --------------  12 g of C

                      3.268 g of CO₂  --------    x

                         x = (3.268 x 12) / 44

                        x = 0.891 g of Carbon

                       12 g of carbon -----------  1 mol

                       0.891 g of C     ----------   x

                       x = (0.891 x 1) / 12

                       x = 0.0743 moles of carbon

2.- Calculate the moles and mass of hydrogen

                      18 g of water --------------- 2 g of H

                      1.672 g of H₂O ------------  x

                      x = (1.672 x 2) / 18

                      x = 0.186 g of hydrogen

                      1 g of hydrogen ------------  1 mol of H

                      0.186 g of H       ------------  x

                      x = (0.186 x 1) / 1

                      x = 0.186 moles of H

3.- Calculate the mass of Oxygen and its moles

Mass of Oxygen = 1.376 - 0.891 - 0.186

                           = 0.299 g of O₂

Moles of Oxygen

                             16 g of Oxygen ---------------- 1 mol

                             0.299 g of O    -----------------  x

                             x = (0.299 x 1) / 16

                             x = 0.019 moles of Oxygen

4.- Divide by the lowest number of moles

Carbon         0.0743/ 0.019 = 3.9 ≈ 4.0

Hydrogen     0.186/ 0.019 = 9.7 = 10

Oxygen         0.019/ 0.019 = 1

5.- Write the empirical formula

                              C₄H₁₀O                  

4 0
3 years ago
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