She originally had $320 in her savings. 48 times 100= 4,800. 4,800 divided by 15=320.
F(t)= $100 x h + 300 A reasonable domain is (1,2,3) and the range is ($400,$500,$600)
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer with Step-by-step explanation:
We are given that an equation of curve

We have to find the equation of tangent line to the given curve at point 
By using implicit differentiation, differentiate w.r.t x
Using formula :



Substitute the value x=
Then, we get


Slope of tangent=m=
Equation of tangent line with slope m and passing through the point
is given by

Substitute the values then we get
The equation of tangent line is given by




This is required equation of tangent line to the given curve at given point.
In order to calculate how much wheat will be stored in each bag, let's divide the total amount of wheat by the number of bags:

Assuming that the amount of wheat each bag can hold is a whole number, so each bag can hold 96 kg (otherwise, each bag would hold 96.875 kg and there would be no wheat left).
Then, to find how much wheat will be left, let's calculate how much the 8 bags will hold, and then we subtract this value from the total:

So there will be 7 kg left.