Answer:
0.0665 days
Explanation:
We are given;
The mean distance from the Earth's center to the moon;a1 = 385000 km
The mean distance from the Earth's center to the space craft;a2 = 6965 km
Formula for kepplers third law is;
T² = 4π²a³/GM
However, the proportion of both distances would be;
(T1)²/(T2)² = (a1)³/(a2)³
Where;
T1 is the period of orbit of the moon around the earth. T1 has a standard value of 27.322 days
T2 is the period of the space craft orbit.
Making T2 the subject, we have;
T2 = √((T1)²×(a2)³)/(a1)³)
Thus, plugging in the relevant values;
T2 = √(27.322² × 6965³)/(385000)³
T2 = 0.0665 days
Answer:
Golfer B hits his golf ball at a higher rate of speed and with more force. This means that golfer B's ball will travel for a longer period of time and a longer distance due to newtons first law, where it says an object in motion stays in motion, with the same speed and in the same direction.
Explanation:
Answer:
1. 60 m/s.
2. 3600 m.
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Time (t) = 2 mins
Final Velocity (v) =?
Distance travelled (s) =?
1. Determination of the velocity at the end of 2 minutes.
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Time (t) = 2 mins = 2 x 60 = 120 secs
Final Velocity (v) =?
v = u + at
v = 0 + (0.5 x 120)
v = 60 m/s
Therefore, the velocity at the end of 2 minutes is 60 m/s.
2. Determination of the distance travelled.
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Final velocity (v) = 60 m/s
Distance travelled (s) =..?
v² = u² + 2as
60² = 0 + 2 x 0.5 x s
3600 = 1 x s
s = 3600 m
Therefore, the distance travelled is 3600 m.
The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
<h3>
Work done by a single force on the chandelier</h3>
The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.
where;
is frictional force = 0 (smooth surface).
<h3>Work done by the two forces</h3>
When the two forces combine to pull the chandelier, the total work done will be shared by the two forces.
Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Learn more about work done here: brainly.com/question/8119756
The force exerted by the laser beam on a completely absorbing target is .
The given parameters;
- <em>power of the laser light, P = 1050 W</em>
- <em>wavelength of the emitted light, λ = 10 μm </em>
The speed of the emitted laser light is given as;
v = 3 x 10⁸ m/s
The force exerted by the laser beam on a completely absorbing target is calculated as follows;
P = Fv
Thus, the force exerted by the laser beam on a completely absorbing target is .
Learn more here:brainly.com/question/17328266